Answer:
sure
Step-by-step explanation:
1) line up 641 and 63
641
x__63_
2) multiply 3 by 1 then 4 then 6 and carry the tenths place number if there is one
1
641
x__63_
1923
3) add a zero under the 3 to hold the ones place and multiply 6 by 1 then 4 then 6 and since we’re working with the tenths place now and dont forget to carry numbers if you need to
2
641
x__63_
1923
38460
4) add your two numbers together
1 1
38460
+___1923_
40383
so that is your answer “40383”
lol sorry that this was so long
Hm. This is an interesting problem.
Let's see if we can express each of these numbers in terms of x and make an algebra equation to help us solve.
Consecutive even numbers increase by 2.
Let's allow x to equal our first number.
Let's allow x + 2 to equal our 2nd number.
Let's allow x + 4 to equal our 3rd number.
When we add those together, their sum need to equal 50 more than the largest integer (our x + 4)
Let's set it up!
x + (x +2) + (x + 4) = (x + 4) + 50
Simplify!
3x + 6 = x + 54
Let's reorganize the left and right sides.
3x - x = 54 - 6
2x = 48
x = 24 (our 1st even number)
Now, let's check our answer!
24 + 26 + 28 = 78
78 - 50 = 28 Our highest integer.
The sum of consecutive integers 24, 26, 28 is 50 more than the highest integer.
Pq + pr = 80 => p (q+r) = 80
pq + qr = 425 => q (p+r ) = 425
Factorize 80 with having one factor as prime number
80 = 2 * 40 = 5 *16
Factrorize 425 with having one factor as prime number
425 = 5 * 85 = 17 * 25...
Therfore, p has to be 2.
q = 17 and r= 23...
p + q +r = 2 + 17+ 23 = 42
4/8 = 0.5
5/12 = 0.42
1/6 = 0.17
<span>Least to Greatest
</span>
1/6, 5/12, 4/8
without using decimal
4/8 = 12/24
5/12 = 10/24
1/6 = 4/24
Least to Greatest
1/6, 5/12, 4/8
Answer:
B and C
Step-by-step explanation:
A is actually 5 so it is an integer and 0 is considered and integer.
