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pashok25 [27]
3 years ago
10

Which of the following could comprised of one atom A.carbon B.salt C.air​

Mathematics
2 answers:
Nataly [62]3 years ago
7 0

Answer:

Carbon

Step-by-step explanation:

Carbon usually exist as single Carbon atoms. Salt consists of Sodium and Chlorine stoms and air is a mixture of gases so it consists of many atoms

valentina_108 [34]3 years ago
3 0
Carbon is Carbon so it's just one atom.
Air is mostly O2, N2, H2O and ....
Salt is NaCl and not one atom ;)
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How to evaluate question number 4
ANTONII [103]

There are 2 ways that spring to mind.

One is to use the definition of the derivative at a point:

f'(c)=\displaystyle\lim_{x\to c}\frac{f(x)-f(c)}{x-c}

In this case, c=0 and f(x)=\sqrt{5-x}. Then

f'(x)=-\dfrac1{2\sqrt{5-x}}\implies f'(0)=\displaystyle\lim_{x\to0}\frac{\sqrt{5-x}-\sqrt5}x=-\dfrac1{2\sqrt5}

- - -

If you don't know about derivative yet (I would think you do, considering this is for a midterm in AP Calc, but I digress), the other way is to rely on algebraic manipulation. Multiply the numerator and denominator by the conjugate of the numerator to get

\dfrac{\sqrt{5-x}-\sqrt5}x\cdot\dfrac{\sqrt{5-x}+\sqrt5}{\sqrt{5-x}+\sqrt5}=\dfrac{\left(\sqrt{5-x}\right)^2-\left(\sqrt5\right)^2}{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac x{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac1{\sqrt{5-x}+\sqrt5}

This is continuous at x=0, so the limit is the value of the expression at x=0:

\displaystyle\lim_{x\to0}\frac{\sqrt{5-x}-\sqrt5}x=-\lim_{x\to0}\frac1{\sqrt{5-x}+\sqrt5}=-\frac1{2\sqrt5}

5 0
3 years ago
COMPLETE<br> The equation X-9=0 has how many <br> real solution(s).
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Answer:

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Step-by-step explanation:

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5 0
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Step-by-step explanation:

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