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Angelina_Jolie [31]

4 years ago

5

Sides AC and BC of triangle ABC are extended as shown. The measures of ∠ACB and ∠ACE are (x+11) and (3x+5), respectively. Find t

he measure of ∠DCB. Find the measure of ∠ECD.

1 answer:

uysha [10]4 years ago

8 0

Angle DCB 123 degrees
angle ECD 52 degrees

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WILL CHOOSE BRAINLIEST. Use the picture and the sentence in the white box to find the combination.

wel

Answer:

It’s ‘ I like you’

Step-by-step explanation:

3 0

3 years ago

The new total is $60, but the sales tax is 5 % of my bill. How much is the sales tax

Dimas [21]

3 dollars. You take 60 and multiply it by 5%

8 0

4 years ago

Given a radius of 9 inches, estimate the length of arc s to the nearest hundredth.

malfutka [58]

The question is incomplete, here is the complete question:

Given a radius of 9 inches intercepted by the central angle 60°. Estimate the length of arc 'S' to the nearest hundredth.

<u>Answer:</u> The arc length of the circle is 9.42 inches

<u>Step-by-step explanation:</u>

To calculate the length of the arc, we use the formula:

$S=2\pi r(\frac{\theta}{360})$

where,

S = arc length = ?

r = radius of the circle = 9 inches

$\theta$ = central angle = 60°

Putting values in above equation, we get:

$S=2\times 3.14\times 9\times (\frac{60}{360})\\\\S=9.42in$

Hence, the arc length of the circle is 9.42 inches

6 0

3 years ago

Read 2 more answers

Use the Chain Rule to find the indicated partial derivatives. u = x2 + yz, x = pr cos(θ), y = pr sin(θ), z = p + r; (partial u)/

devlian [24]

$u(x,y,z)=x^2+yz$

$\begin{cases}x(p,r,\theta)=pr\cos\theta\\y(p,r,\theta)=pr\sin\theta\\z(p,r,\theta)=p+r\end{cases}$

At the point $(p,r,\theta)=(2,2,0)$ , we have

$\begin{cases}x(2,2,0)=4\\y(2,2,0)=0\\z(2,2,0)=4\end{cases}$

Denote by $f_x:=\dfrac{\partial f}{\partial x}$ the partial derivative of a function $f$ with respect to the variable $x$ . We have

$\begin{cases}u_x=2x\\u_y=z\\u_z=y\end{cases}$

The Jacobian is

$\begin{bmatrix}x_p&x_r&x_\theta\\y_p&y_r&y_\theta\\z_p&z_r&z_\theta\end{bmatrix}=\begin{bmatrix}r\cos\theta&p\cos\theta&-pr\sin\theta\\r\sin\theta&p\sin\theta&pr\cos\theta\\1&1&0\end{bmatrix}$

By the chain rule,

$u_p=u_xx_p+u_yy_p+u_zz_p=2xr\cos\theta+zr\sin\theta+y$

$u_p(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_p(2,2,0)=16}$

$u_r=u_xx_r+u_yy_r+u_zz_r=2xp\cos\theta+zp\sin\theta+y$

$u_r(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_r(2,2,0)=16}$

$u_\theta=u_xx_\theta+u_yy_\theta+u_zz_\theta=-2xpr\sin\theta+zpr\cos\theta$

$u_\theta(2,2,0)=-2\cdot4\cdot2\cdot2\sin0+4\cdot2\cdot2\cos0\implies\boxed{u_\theta(2,2,0)=16}$

7 0

3 years ago

9+(-2)x3=7x3 DONT forget pemdas or gemdas

gizmo_the_mogwai [7]

Answer:

The equation is true.

Step-by-step explanation:

First you divide both sides of the equation by 3. This leaves you with 9-2=7 (notice I rewrote 9+(-2) to 9-2, this is because they mean the same thing one is just easier to look at). Then you add 2 to both sides. This cancels the 2 on the left side and makes the rights side a nine. Since both sides leave you with nine this proves are equal, making it a true equation.

6 0

4 years ago