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Korolek [52]
3 years ago
12

How does the endomembrane system work together with the ribosomes? A. takes proteins out of the cell B. provides a protective co

vering C. helps to make food D. obtains energy for the cell
Biology
2 answers:
Reil [10]3 years ago
7 0
<span>The rough endoplasmic reticulum is where the ribosomes will congregate to attach onto mRNA strands and transcribe the mRNA into protein. The smooth endoplasmic reticulum is where the protein made in the rough endoplasmic reticulum are folded. Sorry if this is confusing

</span>
sukhopar [10]3 years ago
7 0

Answer:

provides a protective covering

Explanation:

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A plant that produces wrinkled, green seeds was mated to a plant that produces phenotypically round, yellow seeds. In the F1 gen
sergejj [24]

Answer:

Genotype of the parental plant that produced round, yellow seeds is RRgg

Explanation:

Let us say that allele for round shape (R) is dominant over allele for wrinkled shape(r)

and allele for green color (G) is dominant over allele for yellow color of seed.  

So a wrinkled green seed will have genotype either "rrGG" or "rrGg"

Like wise a round, yellow seeds will have genotype either "RRgg" or "Rrgg"

It is given that In the F1 generation, half of the plants produced round, yellow seeds and the other half produced round, green seeds.

So if a cross is carried between rrGg and RRgg, the following offspring will be produces

rG          rG         rg         rg

Rg RrGg RrGg Rrgg Rrgg

Rg RrGg RrGg Rrgg Rrgg

Rg RrGg RrGg Rrgg Rrgg

Rg RrGg RrGg Rrgg Rrgg

So genotype “RrGg” gives round and green seeds

And genotype “Rrgg” gives round and green seed

Thus, genotype of the parental plant that produced round, yellow seeds is RRgg

5 0
3 years ago
Które cechy kijanki salamandry są wyrazem przystosowania do środowiska jej życia?
alexandr1967 [171]
Sorry but me no get you
6 0
4 years ago
A plant with the dominant trait, wrinkled seeds, is crossed with a plant that has non-wrinkled seeds. All of the offspring are a
laila [671]
The answer is 0 percent.

If we represent dominant trait (wrinkled seeds) with A and recessive trait (non-wrinkled seeds) with a, then genotypes are AA (dominant homozygous), Aa (heterozygous), and aa (recessive homozygous). The phenotype of wrinkled seed is determined by genotypes either Aa or AA. Since the cross of a plant with wrinkled seed with a plant with non-wrinkled sees gives only wrinkled-seeded offspring, the plant with wrinkled seeds must be dominant heterozygous.
Let's look at both examples.
If wrinked-seeded parent contains one non-wrinkled allele, it must be heterozygous (Aa):

Parents:       Aa      x      aa
Offspring:    Aa    Aa    aa   aa

So, the 50% of offspring has wrinkled seeds and 50% has <span>non-wrinkled seeds. 

If </span><span>the wrinkled-seeded parent does not contain any non-wrinkled allele:
</span>Parents:       AA      x      aa
Offspring:    Aa<span>    Aa    Aa   Aa
</span><span>
Thus, al</span><span>l of the offspring are heterozygous and all of them have wrinkled seeds.</span>
3 0
3 years ago
Read 2 more answers
During prophase 1 of meiosis, crossing over between the sister chromatids occurs. What is the purpose of this process
AleksandrR [38]

Crossing over can lead to an abnormal genome if the exchange is not done equally, which can lead to an in-utero death or congenital diseases.

5 0
4 years ago
If all living organisms contain the same DNA how is it that we are all different?
Ber [7]

Answer:

Genes are made up of DNA.. DNA is the molecule that is the hereditary material in all living cells. The color of your hair,skin,eyes etc,, are all controlled in part by your genetic information

Explanation:

7 0
4 years ago
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