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vodomira [7]
3 years ago
12

F+4/g=6 Solve for F

Mathematics
1 answer:
Svet_ta [14]3 years ago
5 0
\dfrac{f+4}{g}=6\ \  \ \ |multiply\ both\ sides\ by\ g\\\\f+4=6g\ \ \ \ |subtract\ 4\ from\ both\ sides\\\\\boxed{f=6g-4}
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Glurpina is a polymorph alien and can grow extra limbs. Right now, she has 3 hands and can shake everyone hand at the alien conf
Wewaii [24]

She can shake everyone's hand by 9/10 hands in 3 minutes.

<h3>What is the unitary method?</h3>

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Glurpina is a polymorph alien and can grow extra limbs.

She has 3 hands and can shake everyone's hand at the alien conference in 10 minutes.

She can shake everyone's hand by 3 hands in 10 minutes.

She can shake everyone's hand by 1 hands in 10 / 3 minutes.

She can shake everyone's hand by how many extra hands in 3 minutes.

= 3/ 10 x 3

= 9/10

Thus, She can shake everyone's hand by 9/10 hands in 3 minutes.

Learn more about the unitary method;

brainly.com/question/23423168

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2 years ago
What is the parent function of the following graph?
Leya [2.2K]

X^4 because it has 4 zeroes ( the graph crosses the x axis 4 times

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3 years ago
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What is statistical power and how would you calculate it?
Natasha_Volkova [10]

Answer:

The statistical power of a hypothesis test is the probability of detecting an effect, if there is a true effect present to detect. Power can be calculated and reported for a completed experiment to comment on the confidence one might have in the conclusions drawn from the results of the study.

I hope it's helpful!

3 0
3 years ago
Someone help me answer this
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65 yards because of a2+b2=c2
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3 years ago
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Two complex numbers are given byz1= 3 +j4 andz2= 2 +j3. Determine in both polar andCartesian forms
Marat540 [252]

Answer:

Cartesian

z₁= 3 +4*j

z₂= 2 +3*j

Polar

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

Step-by-step explanation:

for the complex numbers z the cartesian form of is

z= x + y*j

then

1) z₁= 3 +4*j (cartesian form)

2) z₂= 2 +3*j (cartesian form)

the polar form is

z= r* e^jθ

where

r= √(x²+y²) → r₁ = √(3²+4²) = 5 ,  r₂ = √(2²+3²) = √13

and

θ = tan⁻¹ (y/x)  → θ₁  = tan⁻¹ (4/3)= 0.927 rad , θ₂  = tan⁻¹ (3/2)= 0.982 rad

then

z₁=5 * e^ (0.927*j)

z₁=√13 * e^ (0.982*j)

3 0
3 years ago
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