Question

Points j, k, and L are collinear

Answer 1

Answer:

n=4

JK=12

KL=13

Step-by-step explanation:

Given information: JK=3n and KL=5n-7.

It is given that Points J, K, and L are collinear. It means points J, K and L lie on a straight line.

Using segment addition property we get

$JL=JK+KL$

$JL=3n+5n-7$

$JL=8n-7$

(a)

It is given that JL=25.

$25=8n-7$

Add 7 on both sides.

$32=8n$

Divide both sides by 8.

$\frac{32}{8}=n$

$4=n$

Therefore, the value of n is 4.

(b)

$JK=3n$

$JK=3(4)$

$JK=12$

The value of JK is 12 units.

$KL=5n-7$

$KL=5(4)-7$

$KL=20-7$

$KL=13$

Therefore the value of KL is 13 units.

Answer 2

Answer:

n=4

JK=12

KL=13

Step-by-step explanation:

Since JL=25 and JL=3n+5n-7

Then

3n+5n-7=25 simplifying we get

8n-7=25 subtracting 7 from both sides

8n=32 dividing both sides by 8

n=4

JK?

JK=3n bt n=4

JK=3*4

JK=12

KL?

KL=5n-7

KL=5*4-7

KL=13