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4 years ago

n the pictured triangle, ∠A is 81 degrees and ∠B is 67 degrees. If side a is 34 units long, approximately how long is side b?

Mathematics

1 answer:

Sloan [31]4 years ago

7 0

Step-by-step explanation:

can u also attach the pictured triangle so we can know it exactly

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A triangle with area 45 square inches has a height that is two less than four times the width. Find the width and height of the

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

45 = (b(4b - 2))/2

90 = 4b2 - 2b

4b2 - 2b - 90 = 0

(2b + 9)(2b - 10) = 0

2b + 9 = 0

2b = -9

b = -9/2

If we were looking for zeroes, this would be an answer, but since we're looking for measurement, we don't use negative numbers.

90 = 4b2 - 2b

4b2 - 2b - 90 = 0

(2b + 9)(2b - 10) = 0

2b + 9 = 0

2b = -9

b = -9/2

7 0

3 years ago

Read 2 more answers

Part B if the height of each prism is 10 Cm what is the surface area prism

Evgen [1.6K]

Answer:

Prism A:

$Area = 288cm^2$

Prism B:

$Area =250cm^2$

Step-by-step explanation:

Given

See attachment for prisms

$Height(h) = 10cm$

Required

Determine the surface area of both prisms

Prism A is triangular and as such, the surface area is:

$Area = 2 * A_b + (a + b + c) * h$

Where

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

and

$s = \frac{a + b + c}{2}$

Such that a, b and c are the lengths of the triangular sides of the prism.

From the attachment;

$a = 8; b =6; c =10$

So, we have:

$s = \frac{a + b + c}{2}$

$s = \frac{8 + 6 + 10}{2}$

$s = \frac{24}{2}$

$s = 12$

Also:

$A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}$

$A_b = \sqrt{12 * (12 - 8) * (12 - 6) * (12 - 10)}$

$A_b = \sqrt{576}$

$A_b = 24$

So:

$Area = 2 * A_b + (a + b + c) * h$

$Area = 2 * 24 + (8 + 6 + 10) * 10$

$Area = 288cm^2$

Prism B is a rectangular prism. So, the area is calculated as:

$Area = 2 * (ab + bh + ah)$

From the attachment

$a = b = 5$

$h =10$

So:

$Area =2 * (5 * 5 + 5 * 10 + 5 * 10)$

$Area =250cm^2$

7 0

3 years ago

Is 9.55x10 to the 3rd power greater than less than or equal to 5,900

erastovalidia [21]

Answer:

See below.

Step-by-step explanation:

9.55 * 10^3 = 9550.

So it is greater than 5,900.

5 0

4 years ago

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st

Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so $\mu = 0.5, \sigma = 0.05$ .