(08.01, 08.02, 08.03, 08.05, 08.06 MC)

Mathematics

2 answers:

bagirrra123 [75]4 years ago

8 0

Part A:

x^2y^2 + 6xy^2 + 8y^2

y^2(x^2 + 6x + 8)

y^2(x^2 + 2x + 4x + 8)

y^2[(x + 2)(x + 4)]

Part B:

x^2 + 8x + 16

x^2 + 4x + 4x + 16

(x + 4)(x + 4) = (x + 4)^2

Part C:

x^2 - 16

x^2 and 16 are perfect squares

(x + 4)(x - 4)

Finger [1]4 years ago

3 0

Part a,Factor x2+8x+16
x2+8x+16
=(x+4)(x+4)
Answer:
(x+4)(x+4)

part c,Factor x2−16
x2−16
=(x+4)(x−4)
Answer:
(x+4)(x−4)

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