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3 years ago

Adam has come to town to attend his friend's wedding. He is staying in a hotel. To which person should he offer a tip?

Mathematics

2 answers:

lord [1]3 years ago

3 0

The hotel doorman He did 2 things :)

Fittoniya [83]3 years ago

3 0

<h3>Answer:</h3>

The correct option is:

The hotel doorman for opening the door for him

<h3>Step-by-step explanation:</h3>

A gratuity( also called as a tip) is a sum of money that is given by a client or customer to a service worker in addition to the basic price.

It is given to certain service sector workers for a service performed.

Tips and their amount are a matter of social custom and etiquette, and the custom may vary between countries and settings.

So, Adam should offer a tip to:

the hotel doorman for opening the door for him.

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What is. 5(x-1)+3=3x-2(3-2x) I give Brainliest! Please show your work

garik1379 [7]

Answer:

x=2

Step-by-step explanation:

Expand 5(x-1)+3: 5x-2

5x-2=7x-6

add 2 both sides and simplify

5x=7x-4

subtract 7x from both sides

5x=7x-4-7

___-7____

simplify -2x=4x divide both sides by 2, -2x/-2=-4/-2

x=2

3 0

3 years ago

Read 2 more answers

Find the slope and y-intercept of the line that is perpendicular to y = -x-1 and passes through the point (5,7).

Brums [2.3K]

So we have y=-x-1 this is the same as y=-1(x+1) so it has a slope of -1 this means any line perpendicular will have a slope of 1. now we use this with the point and point slope formula.
recall point slope formula is y-y1=m(x-x1) where (x1,y1) is a point and m is the slope so we find
y-7=1(x-5) we can simplify this into y intercept form by solving for y
so
y=x-5+7
y=x+2
so the line perpendicular has a slope of 1 and a y intercept of 2! :)

5 0

3 years ago

Determine what type of model best fits the given situation: An Internet phone company presently provides service to 5,000 custom

bagirrra123 [75]

Answer:

The best fit is A. Linear model

Step-by-step explanation:

Given:

Monthly Rate = $20, Number of customers = 5000

If there is a decrease of $1 in the monthly rate, the number of customers increase by 500.

To find:

The type of model that best fits the given situation?

Solution:

Monthly Rate = $20, Number of customers = 5000

Let us decrease the monthly rate by $1.

Monthly Rate = $20 - $1 = $19, Number of customers = 5000 + 500 = 5500

Let us decrease the monthly rate by $1 more.

Monthly Rate = $19 - $1 = $18, Number of customers = 5500 + 500 = 6000

Here, we can see that there is a linear change in the number of customers whenever there is decrease in the monthly rate.

We have 2 pair of values here,

x = 20, y = 5000

x = 19, y = 5500

Let us write the equation in slope intercept form:

$y =mx+c$

Slope of a function:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{5500-5000}{19-20}\\\Rightarrow -500$

So, the equation is:

$y =-500x+c$

Putting x = 20, y = 5000:

$5000 =-500\times 20+c\\\Rightarrow c = 5000 +10000 = 15000$

$\Rightarrow \bold{y =-500x+15000}$

Let us check whether (18, 6000) satisfies it.

Putting x = 18:

$-500 \times 18 +15000 = -9000+15000 = 6000$ so, it is true.

So, the answer is:

The best fit is A. Linear model

6 0

4 years ago

A soft drink machine outputs a mean of 2323 ounces per cup. The machine's output is normally distributed with a standard deviati

viktelen [127]

Answer:

Area under the normal curve: 0.6915.

69.15% probability of putting less than 24 ounces in a cup.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 23, \sigma = 2$