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Rashid [163]
3 years ago
11

My number has 2 hundreds, the tens digit has 9 more than the ones digit

Mathematics
2 answers:
Svetach [21]3 years ago
6 0
The number is two hundred ninety- one. 
AnnyKZ [126]3 years ago
4 0
You never told us what number was in the tens place
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Wayne is solving a system of linear equations.
Ulleksa [173]

Answer:

(-2, 6.5)

Step-by-step explanation:

Wayne can follow the line from (-2, 0) up to where it crosses the graphed line. The crossing point is approximately halfway between 6 and 7 on the graph, so can be considered to be 6.5.

If we put x=-2 into the equation and evaluate, we get ...

... y = (-3/4)(-2) +5 = 6/4 +5 = (1 1/2) +5 = 6 1/2

Thus the solution is (-2, 6 1/2).

8 0
4 years ago
The dot plots show the heights of the players on two basketball teams.
olga2289 [7]

Answer: I’m a little late but I also myself just got this answer on a test and was trying to see if it was correct but i narrowed it down to A

Step-by-step explanation:

eliminated answer choices

6 0
3 years ago
Read 2 more answers
-f(3f-7)=0 solve equation<br>​
kenny6666 [7]

Answer:

F=0 or (7/3)

Step-by-step explanation:

When F is 0, the equation reads -0(3(0)-7)=0. The outside 0 will multiply by everything and make it equal 0. When F is 7/3, the inside of the parenthesis read 3(7/3)-7. This equals 7-7. It'll end up being (7/3)0, which equals 0.

3 0
3 years ago
A bullet is fired straight up from a gun with initial velocity 1120 feet per second at an initial height of 8 feet. Use the form
Dafna1 [17]

Answer:

70 seconds

Step-by-step explanation:

Given that;

The initial velocity v_o of the bullet fired = 1120 ft/s

Initial height h = 8 feet

The expression to determine how many seconds it takes the bullet to hit the ground is:

h = -16t^2 +v_ot + 8

Thus;

Replacing the value of v_o =  1120 and h = 0 (i.e. when h =0) in the above expression; we have:

0= -16t^2 +(1120)t + 8

=  -16t^2 +(1120)t + (8-0)

= -16t² + 1120t + 8

mulitiply through by (-)

= 16t² -1120t - 8

Divide through by 8

= 2t² -  140t - 1

The above expression forms a quadratic equation.

where;

a = 2

b = -140

c = - 1

So, by using the quadratic formula \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}, we have:

= \dfrac{-(-140) \pm \sqrt{(-140)^2-4(2)(-1)}}{2(2)}

= \dfrac{140 \pm \sqrt{19600-(-8)}}{4}

= \dfrac{140 \pm \sqrt{19608}}{4}

= \dfrac{140 \pm 140}{4}

=\dfrac{140+ 140}{4} \ \ \ OR \ \ \  \dfrac{140-140}{4}

=\dfrac{280}{4} \ \ \ OR \ \ \  0

= 70

Thus, the time (in seconds) it took the bullet to it the ground = 70 seconds

6 0
3 years ago
Decompose 549 two ways​
RUDIKE [14]

Answer:

not sure if this is what you mean but you could do 500+49 or 510+39

4 0
3 years ago
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