Answer:
The expected number of contracts the sales representative will get this week is 5.22
Step-by-step explanation:
For each client, there are only two possible outcomes. Either there is a sales contract, or there is not. The probability of having a sale contract with each client is independent of other clients. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:

In this problem, we have that:

What is the expected number of contracts the sales representative will get this week?

The expected number of contracts the sales representative will get this week is 5.22
Answer:
Step-by-step explanation:
Given that a manufacturer makes three types of screws
Type A B C Total
Pack 1000 500 800
P for flaw 0.001 0.03 0.005
Pack*p 1 15 4 20
a) Expected total number of defective screws = 20
b) For one pack each no of defective screws =20
Hence for 5 expected number number of packs form each should be 1/3
Answer: B
Step-by-step explanation: 3/8 + 1/16 = 0.4375 and 7/16 = 0.4375
D none of them fit the data set.