Answer:
yes
Step-by-step explanation:
Add them up and you get 13/12, which is more than 1.
Answer:
x = 1 , y = 1 and z = 0
Step-by-step explanation:
-2x+2y+3z=0 ------(1)
-2x-y+z=-3 --------(2)
2x+3y+3z=5 ---------(3)
<u>To find the values of x,y and z</u>
(3) - (2)⇒ 2y + 4z = 2
y + 2z = 1 --------(4)
(1) - (2)⇒ 3y +2z =3 ---(5)
(5) - (4)⇒ 2y = 2
y = 1
Substituting the value of y in (4) we get z =0
Substituting the value of y and z in (1) we get x = 1
Therefore x = 1 , y = 1 and z = 0
Answer:
Step-by-step explanation:
g(t)=t^2 - t
f(x) = (1 + x)
g(f(x)) = f(x)^2 - f(x)
g(f(x)) = (x + 1)^2 - x - 1
g(f(0)) = (0 +1)^2 - x - 1
g(f(0)) = 1 - 1 - 1 = -1
================================
f(x) = 1 + x
f(g(t)) = 1 + g(t)
f(g(t)) = 1 + t^2 - t
f(g(0)) = 1 + 0 - 0
f(g(0)) = 1
The answer I'm getting is 0.
It is 830. ok just put the decimal in the back
