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4 years ago

Need help asap plz <3✨ PLEASE ANSWER THE QUESTION THX :)

Mathematics

2 answers:

Flauer [41]4 years ago

8 0

Answer: positive

Step-by-step explanation:

<em>..because a positivenumber and a positive number make a negitive number and a negitive number and a negitive number makes a positive and a positive number and a negitve number only depens on wich number is bigger so for an example -9 + +11= 20 since 11 is bigger the answer would be positive....</em>

Thepotemich [5.8K]4 years ago

3 0

Answer:

It is positive because negatives cancel out each other

Step-by-step explanation:

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The altitude of a triangle is increasing at a rate of 1.500 centimeters/minute while the area of the triangle is increasing at a

puteri [66]

Answer:

The base of the triangle is shrinking at a rate of $\frac{131}{32}$ centimeters per minute.

Step-by-step explanation:

The formula of the area of a triangle is given by the following expression:

$A = \frac{1}{2}\cdot b \cdot h$

Where:

$A$ - Area of the triangle, measured in square centimeters.

$b$ - Base of the triangle, measured in centimeters.

$h$ - Height of the triangle, measured in centimeters.

The base of the triangle is:

$b = \frac{2\cdot A}{h}$

If $A = 98000\,cm^{2}$ and $h = 8000\,cm$ , the base of the triangle is:

$b = \frac{2\cdot (98000\,cm^{2})}{8000\,cm}$

$b = 24.5\,cm$

The rate of change of the area of the triangle in time, measured in minutes, is obtained after differentiating by rule of chain and using deriving rules:

$\frac{dA}{dt} = \frac{1}{2}\cdot h\cdot \frac{db}{dt} + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}$

$\frac{dA}{dt} = \frac{1}{2} \cdot \left(h\cdot \frac{db}{dt}+b \cdot \frac{dh}{dt} \right)$

The rate of change of the base of the triangle is now cleared:

$2\cdot \frac{dA}{dt} = h\cdot \frac{db}{dt} + b\cdot \frac{dh}{dt}$

$h\cdot \frac{db}{dt} = 2\cdot \frac{dA}{dt}-b\cdot \frac{dh}{dt}$

$\frac{db}{dt} = \frac{2\cdot \frac{dA}{dt} - b \cdot \frac{dh}{dt} }{h}$

Given that $\frac{dA}{dt} = 2000\,\frac{cm^{2}}{min}$ , $b = 24.5\,cm$ , $\frac{dh}{dt} = 1500\,\frac{cm}{min}$ and $h = 8000\,cm$ , the rate of change of the base of the triangle is:

$\frac{db}{dt} = \frac{2\cdot \left(2000\,\frac{cm^{2}}{min} \right)-(24.5\,cm)\cdot \left(1500\,\frac{cm}{min} \right)}{8000\,cm}$

$\frac{db}{dt} = -\frac{131}{32}\,\frac{cm}{min}$

The base of the triangle is shrinking at a rate of $\frac{131}{32}$ centimeters per minute.

5 0

3 years ago

The table contains the proof of the theorem of the relationship between slopes of parallel lines. What is the missing statement

Kipish [7]

Answer:it is the letter A

4 0

4 years ago

Read 2 more answers

Find the midsegment of triangle ABC so that it is parallel to side BC and label it as segment EG on the graph.

Lelechka [254]

Answer:

Coordinate of E:(-2,3) Coordinate of G: (2.5,1.5)

Parallel: slopes both = -1/3

1/2 segment: EG length= 3 BC length=6: This is the only one I'm not sure about.

I will show the work for both the problems down below.

Step-by-step explanation:

Finding coordinates:

1+(-5)/2=-2 5+1/2=3

(-2,3)

1+4/2= 2.5 5+(-2)/2= 1.5

(2.5,1.5)

Show work verifying the EG and BC are parallel:

You can do this by finding the slope

Slop formula (y2-y1)/(x2-x1)

(1.5-3)/(2.5-(-2))

Then simplify

-1.5/2/5= -1/3 which i your slope. You use the same formula and follow thee same steps for the points of BC and both will come up as -1/4 meaning they are parallel.

Show work verifying that EG and BC are parallel:

Use distance formula to find how long each line is

√(x2-x1)^2+(y2-y1)^2

√(2.5-(-2)^2)+(1.5-3)^2

Simplify

√4.5+(1.5)=3

Do the same thing with BC and you will get 6

7 0

3 years ago

Find the value of the expression. 1188÷33

lesya [120]

the answer to 1188/33 is 36

8 0

3 years ago

Read 2 more answers

Bethany s making trail mix with 3 cups of raisins for every 2 cups of peanuts

DaniilM [7]

Answer:

4 cups of raisins

3 cups of dates

6 cups of peanuts

and 2 cups of cashews

ratio cashews to raisins= 2:4

= 1:2

ratio dates to peanuts= 3:6

= 1:2

5 0

4 years ago

Need help asap plz <3✨ PLEASE ANSWER THE QUESTION THX :)​

Need help asap plz <3✨ PLEASE ANSWER THE QUESTION THX :)