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natali 33 [55]
3 years ago
14

Help me with graphing pls

Mathematics
1 answer:
blsea [12.9K]3 years ago
7 0
Graphing what? there isn’t a picture
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Given that the triangles shown below are simiar, what is the value of x?
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B

Step-by-step explanation:

This triangle has been scaled down from triangle one to triangle two. I didn't have a lot of study on this subject, but the answer that makes most sense to me would be B if you want to keep the triangles proportional

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How many terms are in the expression<br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%2B%20xy%20-%20%7By%7D%5E%7B2%7
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a term will be the expression between the + or - signs

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What are two different strategies for finding the product of 472 and 33.
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4. The population of Bay Village is 35,000 today. Every year the
frosja888 [35]

Answer:

Linear Model:   y(x)=35,000+750x

Step-by-step explanation:

In principle <em>Linear Models </em>are employed when we want to define a relationship between an independent and a dependent variable. <em>Linear Models</em> are also known as<em> Functions </em>, where one variable is expressed as a function of <em>at least one</em> other variable. The most common example would be a dependent variable y that is directly linked as a response to any changes of an independent variable x. The most common expression of such relationship would be y=ax where a is the relationship factor between y and x and is also known as the <em>slope </em>of the function (representing a rate of change of that function).

In this question we are told that the population of Bay Village today is 35,000. So we know this is our constant variable, lets call it  b.

Next we know that every year the population is increased by 750 people. So we know that our variable and thus our independent variable is every year which we shall call x and our fixed factor is the 750 increment which we will call a.  

From that we can conclude that:

<em>Year 1 Population: 35,000</em>

<em>Year 2 Population: 35,000 + 750 = 35,750</em>

<em>Year 3 Population: 35,750 + 750 = 36,500 </em>

And so on and so forth.<em> </em>

So we want to express the above as a Linear Model of the form:

<em> y = ax + b   </em>Eqn(1).

Thus from Eqn (1) and all information given (i.e. pluging in values) we finally obtain:

y(x)=35,000+750x

Which for every different value of  x (i.e. every year) we can obtain the new and increased population  y(x).

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