bearing in mind that an x-intercept is when the graph touches the x-axis and when that happens y = 0, and a y-intercept is when the graph touches the y-axis and when that happens x = 0.
![\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{1}{5}}[x-\stackrel{x_1}{(-5)}] \\\\\\ y=-\cfrac{1}{5}(x+5)\implies y = -\cfrac{1}{5}x-1](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%5Cstackrel%7By_1%7D%7B0%7D%3D%5Cstackrel%7Bm%7D%7B-%5Ccfrac%7B1%7D%7B5%7D%7D%5Bx-%5Cstackrel%7Bx_1%7D%7B%28-5%29%7D%5D%20%5C%5C%5C%5C%5C%5C%20y%3D-%5Ccfrac%7B1%7D%7B5%7D%28x%2B5%29%5Cimplies%20y%20%3D%20-%5Ccfrac%7B1%7D%7B5%7Dx-1)
This is the first half of the question.
Let's solve your equation step-by-step.5x=9x3+2x2−5x+4Step 1: Subtract 9x^3+2x^2-5x+4 from both sides.5x−(9x3+2x2−5x+4)=9x3+2x2−5x+4−(9x3+2x2−5x+4)−9x3−2x2+10x−4=0Step 2: Use cubic formula.x=−1.31953Answer:<span>x=<span>−1.31953
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Answer:
4
Step-by-step explanation:
If the tape is 12m,
she hung the tape in between every 3m, and at both ends
0, 3, 6, 9, 12
these are the lengths she hung ribbons at
Total number of ribbons = 4
A is correct
Answer:
15 I just stared so I am bad but I think I am correct
