Answer: Let c represents the time spends in producing a cockpit and p represents the time spends in producing a propulsion system. Thus, According to the question, Machine A ran for 26 hours and produced 4 cockpits and 6 propulsion systems.⇒ 4 c + 6 p = 26And, Machine B ran for 56 hours and produced 8 cockpits and 12 propulsion systems,⇒ 8 c + 12 p = 56Hence, the system of equations that will be used to find a unique amount of time that it takes each machine to produce a cockpit and to produce a propulsion system is,4 c + 6 p = 26, 8 c + 12 p = 56But both lines are parallel,Hence there is no solution of this system,Therefore, we can not solve for a unique amount of time that it takes each machine to produce a cockpit and to produce a propulsion system.
V = lwh
V = (x + 2)(x + 3)(x)
V = (x)(x^2 + 3x + 2x + 6)
V = (x^3 + 3x^2 + 2x^2 + 6x)
V = x^3 + 5x^2 + 6x
All you do is foil the dimensions together and then combine like terms. Hope this helps!
Answer:
95.
Step-by-step explanation:
2.85 times 10⁶=2850000
then 2850000÷30,000=9.5
so either 95 or 9.5
Which one sounds correct should be.
Answer:
a. 21 2/6
Step-by-step explanation:
5 2/6 multiplied by 4 is 21 2/6
Answer:
320
Step-by-step explanation:
300+3x40=120-25x4
300+120-25x4=100
320
