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3 years ago

Choose the appropriate description for the equation.

Mathematics

2 answers:

nignag [31]3 years ago

5 0

Circle
^^^^^^^^^^^^^^^^

Dmitry_Shevchenko [17]3 years ago

3 0

100% Circle!!!!!!!!!!!!!!!!!!!!!!!!

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Help please with #3

Alenkasestr [34]

Answer: x = 2a over b + c

Step-by-step explanation:

1. Multiply both sides by two. This cancels out 2 and turns a into 2a. It should look like 2a = bx + cx

2) Since both b and c have x’s, we turn it into (b + c)x

3. Then divide both sides by b+c to get 2a over b + c = x

6 0

2 years ago

PLZ HELP!!!!!! I THINK ITS TRUE BUT IM NOT SURE

suter [353]

Yes it is true! it is true because two different numbers go to the same number, if it was false it would have to be the one number to two different numbers.

Hope that made sense!

5 0

3 years ago

What are the solutions to the equation (2x-5)(3x-1)=0?

lutik1710 [3]

(2x-5)(3x-1)=0

2x-5 = 0 or 3x-1= 0
2x = 5 3x = 1
x = 5/2 x = 1/3

Answer: x=5/2; x=1/3

6 0

2 years ago

Read 2 more answers

Solve for x in the equation x^2-14+31=63

Bingel [31]

To solve for a variable, you need to get it (x) by itself.

x² - 14 + 31 = 63 Add 31 to -14
x² + 17 = 63 Subtract 17 from both sides of the equation
x² = 46 Square root both sides
x = $\pm \sqrt{46}$

Check your work by plugging in $\sqrt{46}$ for x and then $- \sqrt{46}$ .

$\sqrt{46}$ ² - 14 + 31 = 63 Square $\sqrt{46}$
46 - 14 + 31 = 63 Subtract 14 from 46
32 + 31 = 63 Add
63 = 63

$- \sqrt{46}$ ² - 14 + 31 = 63 Square $- \sqrt{46}$
46 - 14 + 31 = 63 Subtract 14 from 46
32 + 31 = 63 Add
63 = 63

So, x is $\sqrt{46}$ and $- \sqrt{46}$ .

3 0

3 years ago

According to the number line, which statement MUST be true? A) A < 0 B) B > 10 C) C < 15 D) D > 15

Elena L [17]

According to the number line, the statement that MUST be true- is (C) C < 15

c) We can see that √C is almost equal to 4, and 4^2 = 16, so most likely, C is bigger than 15, so this is true

Step-by-step explanation:

As you know, in the number line we are looking at the roots of the numbers, and as you know; (√A)^2 = A, so using this, we can analyze each option:

a) A can not be less than zero, because √A is bigger than zero.

b) we can see that √B is smaller than 3, and 3^2 = 9, so B must be smaller than 9, and then, smaller than 10.

c) We can see that √C is almost equal to 4, and 4^2 = 16, so most likely, C is bigger than 15, so this is true

d) we can see that √D is bigger than 4, and using the same reasoning as before, we can see that D is bigger than 16, and 16 is bigger than 15, so D > 15 is false

6 0

2 years ago

Read 2 more answers