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vladimir1956 [14]

3 years ago

6

A) 9 B) 0 C) Undefined D) 6

1 answer:

mezya [45]3 years ago

8 0

Answer:

<h2>B) 0</h2>

Step-by-step explanation:

The slope of a horizontal line is equal to 0.

The slope of a vertical line is undefined.

The formula of a slope:

$m=\dfrac{y_2-y_!}{x_2-x_1}$

Put the coordinates of the pojnts from the graph (2, 9) and (4, 9):

$d=\dfrac{9-9}{4-2}=\dfrac{0}{2}=0$

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Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1

Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(c) 0.0039

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

$P(x=r)=^nC_rp^rq^{n-r}$

(a) Exactly two will be drunken drivers.

$P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}$

$P(x=2)=66(0.2)^{2}(0.8)^{10}$

$P(x=2)=\approx 0.28347$

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

$P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)$

$P(x=3\text{ or }x=4)=P(x=3)+P(x=4)$

Using binomial we get

$P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}$

$P(x=3\text{ or }x=4)=0.236223+0.132876$

$P(x=3\text{ or }x=4)\approx 0.369099$

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

$P(x\geq 7)=1-P(x$

$P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]$

$P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]$

$P(x\leq 7)=1-[0.9961]$

$P(x\leq 7)=0.0039$

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

$P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)$

$P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315$

$P(x\leq 5)=0.9806$

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

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2 years ago

Find the area of the shaded regions. Give your answer as a completely simplified

Snezhnost [94]

Do the area of the circle as a whole minus (72/360 x radius^2) and then minus the other grey area.

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2 years ago

What is 2+(9-5)x7-3/4

Cloud [144]

I got 9.75 hope it's right

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2 years ago

What is 9 to the power of 6 divided by negative 2 to the power of 3?

Dafna11 [192]

The answer is -66430.125

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3 years ago

Read 2 more answers

Find 2 numbers a and b such that (a-b)^2 < (a+b)(a-b)< (a+b)^2 Find two numbes a and b such that this is not true

Svet_ta [14]

Suppose for the moment that the inequality holds for all $a,b$ :

$(a-b)^2$

Expanding everything gives

$a^2-2ab+b^2$

$\implies-ab$

In particular, the inequality says that $-ab$ for any choice of $a,b$ . But if $a$ and $b>0$ , then $-ab>0$ while $ab$ .

So one possible choice of $a,b$ could be $a=-1$ and $b=1$ . Then we get

$(-1-1)^2=4$

$(-1+1)(-1-1)=2$

$(-1+1)^2=0$

but clearly it's not true that $4$ .

8 0

2 years ago