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vladimir1956 [14]
3 years ago
6

A) 9 B) 0 C) Undefined D) 6

Mathematics
1 answer:
mezya [45]3 years ago
8 0

Answer:

<h2>B) 0</h2>

Step-by-step explanation:

The slope of a horizontal line is equal to 0.

The slope of a vertical line is undefined.

The formula of a slope:

m=\dfrac{y_2-y_!}{x_2-x_1}

Put the coordinates of the pojnts from the graph (2, 9) and (4, 9):

d=\dfrac{9-9}{4-2}=\dfrac{0}{2}=0

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How to create a number line with -4 less than r
V125BC [204]

when it tells you what R is then you show a number line with -4 less then R

7 0
2 years ago
Given: AABC, m_ACB=90°,<br> CD 1 AB, m ZACD=60º,<br> BC = 6 cm<br> Find: CD, Area of AABC
just olya [345]

Answer:

Look below

Step-by-step explanation:

Given that CDB is 90 degrees, ACB is 90 degrees, and ACD is 60 degrees, we can determine that DCB = 90-60 = 30 degrees.

This means triangle BCD is a 30-60-90 (angle measures) right triangle

The proportions of the sides (from smallest to largest) is

x:x√3:2x

We are given that BC = 6 cm. This means...

2x=6

x=3

This means DB is 3 cm and CD is 3√3 cm

Using the linear pair theorem, we can find that Angle CDA is 90 degrees. This means ACD is also a 30-60-90 triangle.

x=3√3

x√3=9

2x=6√3

Now we need to find AB

AB = AD + DB

AB = 9 + 3

AB = 12 cm

Area = \frac{1}{2} bh = \frac{1}{2}(12)(3\sqrt3)=6(3\sqrt3)=18\sqrt3

8 0
3 years ago
How do you simplify this?<br>x²y+xy² / y²+2/5 × xy​​​
polet [3.4K]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

Factor the expressions that are not already factored.

_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

\sf \: x ^ { 2 } y + x y ^ { 2 }

Factor out xy.

\sf \: xy\left(x+y\right)

<u>DENOMINATOR</u> \downarrow

\sf{ y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy \\

Factor out 1/5.

\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

_____

Continuing...

\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

Cancel out y in both the numerator and denominator.

\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

Expand the expression.

\sf\frac{x^{2}+xy}{\frac{2}{5}x+y}  \\

This can further simplified to as \downarrow

=    \boxed{\boxed{\bf\frac{5x\left(x  +y\right)}{2x+5y}}}

3 0
3 years ago
Check my answer. I think it C but i really don't know.
Tamiku [17]

Answer:

A

Step-by-step explanation:

The correct answer is A.

Try breaking the shape into other shapes that you can find the area for and then adding them together.

5 0
3 years ago
Read 2 more answers
Solve the system of equations using the addition method.
stepladder [879]

Answer:

A) 5x - 2y = 12

B) 3x + 2y = 36  Adding both equations eliminates "y"

8x = 48

x = 6   Putting x=6 into equation B we get

3*6 + 2y = 36

2y = 18

y = 9

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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