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3 years ago

How do I graph this equation on a graph

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

8 0

Answer:

The equation is in standard form. You will have to convert it to slope intercept form, which is -0.125x + 3.75 = y

Step-by-step explanation:

s = x and a = y, therefore 0.5x + 4y = 15

0.5x + 4y = 15

0.5x + 4y = 15 first subtract 0.5x

4y = -0.5x + 15 then divide all by 4

y = -0.125x + 3.75 slope intercept form

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The graph of a direct variation equation is a line through the origin. The slope of the graph of y = ax is a. through the point (4,6). Write the direct variation equation and find the value of y when x =24.

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4 years ago

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Step-by-step explanation:

$4x^2+24x+13=2x^2+6\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\\4x^2+24x+13-6=2x^2+6-6\\Simplify\\4x^2+24x+7=2x^2\\\mathrm{Subtract\:}2x^2\mathrm{\:from\:both\:sides}\\4x^2+24x+7-2x^2=2x^2-2x^2\\Simplify\\2x^2+24x+7=0\\\mathrm{Solve\:with\:the\:quadratic\:formula}\\Quadratic\:Equation\:Formula\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=24,\:c=7:\quad x_{1,\:2}=\frac{-24\pm \sqrt{24^2-4\cdot \:2\cdot \:7}}{2\cdot \:2}\\x=\frac{-24+\sqrt{24^2-4\cdot \:2\cdot \:7}}{2\cdot \:2}:\quad \frac{-12+\sqrt{130}}{2}\\x=\frac{-24-\sqrt{24^2-4\cdot \:2\cdot \:7}}{2\cdot \:2}:\quad -\frac{12+\sqrt{130}}{2}\\The\:solutions\:to\:the\:quadratic\:equation\:are:\\x=\frac{-12+\sqrt{130}}{2},\:x=-\frac{12+\sqrt{130}}{2}\\\\quad x=-0.29912\ ,\:x=-11.70087$

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3 years ago

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Sloan [31]

1. write it as it is
2. 70.04 since to round you go two decimal places and because the place after that is higher than 5 you round 3 up to 4.
3. DNE since you can’t divide any number by 0

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