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fredd [130]
3 years ago
9

Which statement belongs in the intersection of the Venn Diagram? (4 points)

Mathematics
1 answer:
Ahat [919]3 years ago
8 0
I believe its the second choice.
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4/65 with remeinders
zavuch27 [327]
I think it’s 16 remainder 1
4 0
2 years ago
Mohammad divide Rs 82000 into two parts such that the amounts at 5% per annum compound interest in 2 years and 3 years are equal
lara [203]

Answer:

Rs 42000 and Rs 40000

Step-by-step explanation:

Given that Rs 82000 is divided into two parts.

Let the first part be Rs x which is compounded annually at the interest of 5% per annum for 2 years.

The rate of interest = 5%=0.05

The total amount after 2 years = x(1+0.05)^{2}\cdots(i)

The other part is Rs 82000-x which is compounded annually at the interest of 5% per annum for 3 years.

The total amount after 3 years = (82000-x)(1+0.05)^{3}\cdots(ii)

As both the amounts are equal, so from equation (i) and (ii)

x(1+0.05)^{2}=(82000-x)(1+0.05)^{3} \\\\x(1.05)^{2}=82000(1.05)^{3} -x(1.05)^{3} \\\\x(1.05^2+1.05^3)=82000\times 1.05^3 \\\\x(2.260125)=94925.25 \\\\x=94925.25/2.260125 \\\\

x= 42000

And the other part = 82000-42000 = Rs 40000

Hence, he divides the money as

Rs 42000 at 5% per annum compound interest in 2 years and

Rs 40000 at 5% per annum compound interest in 3 years.

4 0
2 years ago
(4z^5 - 14z^4 + 10z^3 - 16z^2 + 41z - 2) / (z - 2)
r-ruslan [8.4K]

Answer:

4z4−6z3−2z2−20z+1

Step-by-step explanation:

4z5−14z4+10z3−16z2+41z−2

z−2

=

4z5−14z4+10z3−16z2+41z−2

z−2

=

(z−2)(4z4−6z3−2z2−20z+1)

z−2

=4z4−6z3−2z2−20z+1

(theres no more like terms so u cant)

4 0
2 years ago
There are 210210210 students in a twelfth grade high school class. 909090 of these students have at least one sister and 1051051
BlackZzzverrR [31]

Answer:

(1) The value of P (A) is 0.4286.

(2) The value of P (B) is 0.50.

(3) The value of P (A ∩ B) is 0.2143.

(4) The the value of P (B|A) is 0.50.

(5) The events <em>A</em> and <em>B</em> are independent.

Step-by-step explanation:

The events are defined as follows:

<em>A</em> = a student in the class has a sister

<em>B</em> = a student has a brother

The information provided is:

<em>N</em> = 210

n (A) = 90

n (B) = 105

n (A ∩ B) = 45

The probability of an event <em>E</em> is the ratio of the favorable number of outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

The conditional probability of an event <em>X</em> provided that another event <em>Y</em> has already occurred is:

P(X|Y)=\frac{P(A\cap Y)}{P(Y)}

If the events <em>X</em> and <em>Y</em> are independent then,

P(X|Y)=P(X)

(1)

Compute the probability of event <em>A</em> as follows:

P(A)=\frac{n(A)}{N}\\\\=\frac{90}{210}\\\\=0.4286

The value of P (A) is 0.4286.

(2)

Compute the probability of event <em>B</em> as follows:

P(B)=\frac{n(B)}{N}\\\\=\frac{105}{210}\\\\=0.50

The value of P (B) is 0.50.

(3)

Compute the probability of event <em>A</em> and <em>B</em> as follows:

P(A\cap B)=\frac{n(A\cap B)}{N}\\\\=\frac{45}{210}\\\\=0.2143

The value of P (A ∩ B) is 0.2143.

(4)

Compute the probability of <em>B</em> given <em>A</em> as follows:

P(B|A)=\frac{P(A\cap B)}{P(A)}\\\\=\frac{0.2143}{0.4286}\\\\=0.50

The the value of P (B|A) is 0.50.

(5)

The value of P (B|A) = 0.50 = P (B).

Thus, the events <em>A</em> and <em>B</em> are independent.

6 0
3 years ago
Solve the equation f(x)=2/3x+3
Soloha48 [4]

Answer:

You can't solve this because it's alreadying in simpalest form.  

Step-by-step explanation:

8 0
3 years ago
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