The fraction of offspring with black coat color and straight fur is 9/16.
Explanation:
Information given:
black coat colour and straight fur - dominant genotype BBCC, BbCc
yellow coat colour and curly fur - recessive genotype bbcc
Both the traits are independently assorted. The fur colour and fur type is not present on the same chromosome and are not sex linked.
The genotype of the parents are:
BbCc X BbCc
Punnet square shows:
BC Bc bC bc
BC BBCC BBCc BbCC BbCc
Bc BBCc BBcc BbCc Bbcc
bC BbCC BbCc bbCC bbCc
bc BbCc Bbcc bbCc bbcc
9 BLACK STRAIGHT
3 BLACK CURLY
3 YELLOW STRAIGHT
1 YELLOW CURLY
9/16 is the fraction of progeny to be black coat colour and straight fur.
Answer:
I think C because it is underlined and the species name is written in lower case letters and the genus name the first letter is written in upper case letters.
Answer:
I know that the nucleus is the big boss of the cell, and the chlord past is ONLY in plants
Answer:
5%
Explanation:
Frequency of white tigers = 4%
population of tigers = 200
number of heterozygotes = 10
<u>Determine the actual genotype frequency of Heterozygotes </u>
frequency of heterozygotes = Number of heterozygotes / population
= ( 10 / 200 ) * 100
= 0.05 * 100 = 5%
