<h3>60 liters of 40 % dye solution is mixed with 200 liters of 53 % dye solution to get 260 liters of 50 % dye solution</h3><h3><u>Solution:</u></h3>
From given,
Final solution is 260 liter
Let x be the liters of 40 % dye solution
Then, (260 - x) is the liters of 53 % dye solution
Therefore, according to question,
x liters of 40 % dye solution is mixed with (260 - x) liters of 53 % dye solution to get 260 liters of 50 % dye solution
<h3><u>Thus we frame a equation as:</u></h3>40 % of x + 53 % of (260 - x) = 50 % of 260
Solve for "x"
Thus 60 liters of 40 % dye solution is used
Then, (260 - x) = 260 - 60 = 200
Thus 200 liters of 53 % dye solution is used