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Feliz [49]
3 years ago
10

What is the best estimate for the product of 289 and 7

Mathematics
2 answers:
Daniel [21]3 years ago
5 0
300x7=3500 would be the answer
Nat2105 [25]3 years ago
4 0
290 * 7 = 1400 + 630 = 2,030
2030 - 7 = 2,023
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Find the area (DO NOT label answers)<br> 16 yd<br> 6 yd<br> 11 yd
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Answer:

The area would be 48.

Step-by-step explanation:

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2 years ago
100 POINTS
olga nikolaevna [1]

Answer:

5.2

Step-by-step explanation:

To find the height of the plant after 7 weeks, we need to find out the equation of the line of best fit and plug in 7 for x. We already have our y - intercept, which is 1,  and we have a point on the x axis for which the y coordinate is an integer, (5, 4). Since we already have the y - intercept of +1 we have y = mx + 1. Since this applies to (5,4) we can plug this in to our equation. This is then 4 = 5m + 1. Subtracting 1 from both sides, we get 3 = 5m. Dividing by 5, we receive m = 3/5. Since now we have our slope, we can plug in 7 and find out our answer. Plugging in 7 we receive, y = 3/5 * 7 + 1, which is equal to y = 4.2 + 1. This means that y = 5.2, so 5.2 is our answer.

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3 years ago
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Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.
fenix001 [56]

Answer:

The angle between vector \vec{u} = 5\, \vec{i} - 8\, \vec{j} and \vec{v} = 5\, \vec{i} + \, \vec{j} is approximately 1.21 radians, which is equivalent to approximately 69.3^\circ.

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

  • their dot products, and
  • the product of their lengths.

To be precise, if \theta denotes the angle between \vec{u} and \vec{v} (assume that 0^\circ \le \theta < 180^\circ or equivalently 0 \le \theta < \pi,) then:

\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}.

<h3>Dot product of the two vectors</h3>

The first component of \vec{u} is 5 and the first component of \vec{v} is also

The second component of \vec{u} is (-8) while the second component of \vec{v} is 1. The product of these two second components is (-8) \times 1= (-8).

The dot product of \vec{u} and \vec{v} will thus be:

\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}.

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both \vec{u} and \vec{v}:

  • \| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}.
  • \| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}.

<h3>Angle between the two vectors</h3>

Let \theta represent the angle between \vec{u} and \vec{v}. Apply the formula\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} to find the cosine of this angle:

\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}.

Since \theta is the angle between two vectors, its value should be between 0\; \rm radians and \pi \; \rm radians (0^\circ and 180^\circ.) That is: 0 \le \theta < \pi and 0^\circ \le \theta < 180^\circ. Apply the arccosine function (the inverse of the cosine function) to find the value of \theta:

\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ .

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3 years ago
Can someone explain box plots
slamgirl [31]

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3 years ago
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velikii [3]
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With 18.93 gal, he can drive
18.93 gal * 21 mpg = 292.5 miles

3 0
3 years ago
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