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Semmy [17]
3 years ago
7

Determine the slope and y-intercept of the line represented by the linear equation: 1/2y + 2 = 0. Graph the line using the slope

and y-intercept. Describe, in complete sentences, what type of linear relationship the solutions (points) of the line have with each other. Choose two points on the line and prove that they are solutions of the linear equation.
Complete your work in the space provided or upload a file that can display math symbols if your work requires it.
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Answer: This isn't an answer but i have had trouble with this problem. There is no slope because there is not x in the equation. That is all I know, I'm sorry.

Step-by-step explanation:

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kozerog [31]

if the equation has a slope of 0, then it's a horizontal line, and in this case, that line is 1 because 1 = 0+B and b=1

the answer is y=1

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What is the equation for this word problem?:
Wittaler [7]

Answer:

equation:  C = 15 - R

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C = 8

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Mice21 [21]

Answer:

B. is greater than

Step-by-step explanation:

As the graph of function f(x) is a parabola, so that the equation of function f(x) is: f(x) = ax^{2} +bx+c

As it can be seen in thee figure, the graph of function f(x) cross points (0;8) ;(-2; 0) and (4;0)

=> f(0) = 8; f(-2) = 0; f(4) = 0

We have:

  • f(x=0) = a x 0 + b x 0 + c = 8  => c = 8
  • f (x=-2) = a(-2)^{2} -2b+c = 4a -2b + 8 = 0
  • f (x=4) = a(4)^{2} +4b +c = 16a + 4b + 8 = 0

We have:

+) 4a -2b + 8 = 0 => 2 x (4a -2b + 8) = 8a - 4b + 16 = 0 (1)

+) 16a + 4b + 8 = 0 (2)

We take (2) minus (1)

=> (16a + 4b + 8) - (8a - 4b + 16) = 0

=> 8a - 8 = 0 => a = 1

Replace a = 1 into (1)

=> 8 x 1 - 4b + 16 = 0 => b = 6

So that:  f(x) = x^{2} + 6x +8

f (2) = 2^2 + 6 x 2 + 8 = 24

g (2) = 3 -2 + 2 = 3

<em>=> f(2) is greater than g(2)</em>

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3 years ago
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Look up how to make a histogram and put all the numbers 10 and 12 or whatever
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