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4 years ago

Line CD passes through points C(3,-5) and D(6,0). What is the equation of the line CD in standard form?

Mathematics

2 answers:

Serggg [28]4 years ago

8 0

64 because it’s going to be at the rate of 3

Vikentia [17]4 years ago

4 0

Answer:

y=5/3x-10

Step-by-step explanation:

Slope formula (y2-y1)/(x2-x1) give you a slope of 5/3. Then solve for y-int

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12. If Bill wears a green shirt, then he will pass the test. Bill wore a

BigorU [14]

Wouldn’t it just be a and b

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3 years ago

Read 2 more answers

At a gig 0.4 of the audience were female. If there were 100 more male audience members than female, how many were there in the a

pickupchik [31]

Number of females = f
Total number of people in audience = n

0.4n = f
f + (f+ 100) = n
2f + 100 = n

Find n:
f = 0.4n --> Replace f with 0.4n in the equation 2f +100 = n

2(0.4n) + 100 = n --> Multiply out the brackets
0.8n + 100 = n --> Subtract 0.8n from both sides
100 = 0.2n --> To get n, multiply both sides by 5
n = 500

There were 500 people in the audience.

3 0

4 years ago

A barber has already cut for peoples hair today. Every 10 minutes another person comes to the Barber to get a haircut. Write

Alexeev081 [22]

Answer:

Ans. (1) For preparing vaccines, in olden days,microbes were injected in the bodies of horses ormonkeys. These laboratory animals used to makeantibodies to defend these microbes. Antibodies areproteins which can act against the disease-causinggerms. These antibodies were extracted from theblood of these animals and were used as vaccines.(2) Now-a-days with the advent of biotechnology,the vaccines are manufactured in laboratories withthe help of bacteria. For this purpose, a detailedstudy of the disease causing germ is undertaken.The genes and the DNA of such microbes arethoroughly explored. Then based on thisinformation, proteins which can act against suchmicrobes are synthetically prepared in thelaboratories. The safe vaccine is produced in such away which can defend the body against infections.3) Some types of vaccines are prepared from theextracts of germs. These germs or microbes aredeactivated and made dormant. When they areinjected in the body of a person, they initiate thedefending action. The body of such vaccinatedperson, already develops the antibodies in his or herbody. When in future, this person is again attackedby similar germs the defence starts immediately andthe person does not become sick.

7 0

3 years ago

Can someone help me with this worksheet please!!!!

Marat540 [252]

(1) The missing term in the sequence, a₁₂ = 0.8.

(2) The missing term in the sequence, a₈ = 102.5.

(3) The missing term in the sequence, a₈ = 111.

(4) The missing term in the sequence, a₁₂ = -19.

(5) The missing term in the sequence, a₁₂ = 94.

(6) The missing term in the sequence, a₆ = 40.

(7) The missing term in the sequence, a₃₆ = -52.

(8) The missing term in the sequence, a₂₁ = -58.

<h3>Missing term of the sequence</h3>

The missing term in the sequence is determined as follows;

Tₙ = a + (n - 1)d

T₄ = a + 3d

18.4 = a + 3d ---(1)

T₅ = a + 4d

16.2 = a + 4d ---(2)

subtract (1) from (2)

-2.2 = d

18.4 = a + 3(-2.2)

a = 25

a₁₂ = a + 11d

a₁₂ = 25 + 11(-2.2)

a₁₂ = 0.8

a₂ = a + d

57.5 = a + d -- (1)

a₅ = a + 4d

80 = a + 4d --- (2)

solve (1) and (2)

d = 7.5

a = 50

a₈ = a + 7d

a₈ = 50 + 7(7.5)

a₈ = 102.5

a₁₀ = a + 9d

141 = a + 9d --- (1)

a₁₃ = a + 12d

186 = a + 12d --- (2)

Subtract (1) from (2)

d = 15

a = 6

a₈ = a + 7d

a₈ = 6 + 7(15)

a₈ = 111

a₂₂ = a + 21d

-49 = a + 21d ---- (1)

a₂₅ = a + 24d

-58 = a + 24d --- (2)

subtract (1) from (2)

d = -3

a = 14

a₁₂ = a + 11d

a₁₂ = 14 + 11(-3)

a₁₂ = -19

a₄ = a + 3d

-2 = a + 3d --- (1)

a₈ = a + 7d

46 = a + 7d ---- (2)

Subtract (1) from (2)

d = 12

a = -38

a₁₂ = a + 11d

a₁₂ = -38 + 11(12)

a₁₂ = 94

a₉ = a + 8d

64 = a + 8d --- (1)

a₁₂ = a + 11d

88 = a + 11d --- (2)

Subtract (1) from (2)

d = 8

a = 0

a₆ = a + 5d

a₆ = 0 + 5(8)

a₆ = 40

a₂₀ = a + 19d

-4 = a + 19d ---- (1)

a₂₃ = a + 22d

-13 = a + 22d --- (2)

Subtract (1) from (2)

d = -3

a = 53

a₃₆ = a + 35d

a₃₆ = 53 + 35(-3)

a₃₆ = -52

a₂₈ = a + 27d

5 = a + 27d ---- (1)

a₃₃ = a + 32d

50 = a + 32d --- (2)

Subtract (1) from (2)

d = 9

a = -238

a₂₁ = a + 20d

a₂₁ = -238 + 20(9)

a₂₁ = -58

Learn more about arithmetic progression here: brainly.com/question/6561461

#SPJ1

5 0

3 years ago

Factor the expression. If the expression cannot be factored, say so.

tino4ka555 [31]

Delta = 25 - 16 = 9 => $\sqrt{Delta} = 3;$
$x_{1} = (-5 + 3)/4 = -1/2 and x_{2} = (-5 -3)/4 = -2;$ ;
=> 2 $x^{2} + 5x + 2 = 2(x+1/2)(x+2).$ = (2x+1)(x+2).

8 0

4 years ago