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4 years ago

What id the answer to this equation? Please show your solution. tan x = -sqrt(3).

1 answer:

7 0

This problem is all about trigonometric measurement of the angle c where as tan x = - sqrt(3). Base on my calculation and following some theories about angles of the circles, the value of x = 2pi/3 and 5pi/3. I hope you are satisfied with my answer and feel free to ask for more

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Evaluate the function f(x) = 2x3 - 6x + 1 for f(-2).

erma4kov [3.2K]

Answer:

- 3

Step-by-step explanation:

$f(x) = 2 {x}^{3} - 6x + 1 \\ plugging \: x = - 2 \\ f( - 2) = 2( { - 2})^{3} - 6( - 2)+ 1 \\ = 2 \times ( - 8) + 12 + 1 \\ = - 16 + 13 \\ = - 3 \\ f( - 2) = - 3$

7 0

4 years ago

Express each x in terms of y: 1. 2x - 3 = y 2. 2 + 2x -1 = 4y 3. 2A + 4x + 3B = 10

jeka57 [31]

Answer:

1/2y+3/2

2y+-1/2

-3/2b-2x+5

Step-by-step explanation:

4 0

3 years ago

Prove quadrilateral WXYZ is a rhombus.

Tatiana [17]

Answer:

To prove a quadrilateral is a rhombus, here are three approaches:

Show that the shape is a parallelogram with equal length sides; 
Show that the shape is a parallelogram with equal length sides; Show that the shape's diagonals are each others' perpendicular bisectors; or
Show that the shape is a parallelogram with equal length sides; Show that the shape's diagonals are each others' perpendicular bisectors; orShow that the shape's diagonals bisect both pairs of opposite angles.

4 0

3 years ago

Noah puts $500.00 into an account to use for school expenses. The account earns 3% interest, compounded annually. How much will

alexdok [17]

Step-by-step explanation:

3 0

3 years ago

Randomly selected students participated in an experiment to test their ability to determine when one minute (or sixty seconds)

zalisa [80]

Answer: $(57.41,\ 62.19)$

Step-by-step explanation:

Given : Sample size : $n=40$

Sample mean : $\overline{x}=59.8\text{ seconds}$

Standard deviation : $\sigma =9.2\text{ seconds}$

Significance level : $\alpha=1-0.9=0.1$

Critical value : $z_{\alpha/2}=1.645$

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=59.8\pm(1.645)\dfrac{9.2}{\sqrt{40}}\\\\\approx59.8\pm2.39\\\\=(59.8-2.39,\ 59.8+2.39)\\\\=(57.41,\ 62.19)$

Hence, a 90% confidence interval estimate of the population mean of all students = $(57.41,\ 62.19)$

6 0

3 years ago