1 ft is the answer hope it helps
An expression for the square of h is given by
![h^2](https://tex.z-dn.net/?f=h%5E2)
.
Therefore, an expression for the product of the square of h and 8 is given by
![8h^2](https://tex.z-dn.net/?f=8h%5E2)
.
Answer:
B because 5/6 is roughly .83, which is bigger than .8
Step-by-step explanation:
The solution set is
![c \geq 5](https://tex.z-dn.net/?f=c%20%5Cgeq%205)
, meaning that all
![c](https://tex.z-dn.net/?f=c)
at least
![5](https://tex.z-dn.net/?f=5)
satisfy this constraint.
If
![c=5](https://tex.z-dn.net/?f=c%3D5)
, we have
![x < 5](https://tex.z-dn.net/?f=x%20%3C%205)
and
![x > 5](https://tex.z-dn.net/?f=x%20%3E%205)
, meaning
![x](https://tex.z-dn.net/?f=x)
has to be both greater than and less than
![5](https://tex.z-dn.net/?f=5)
, which is impossible. If
![c](https://tex.z-dn.net/?f=c)
is any greater,
![x > c > 5](https://tex.z-dn.net/?f=x%20%3E%20c%20%3E%205)
, so
![x](https://tex.z-dn.net/?f=x)
still must be greater and less than
![5](https://tex.z-dn.net/?f=5)
at the same time. So for all
![c \geq 5](https://tex.z-dn.net/?f=c%20%5Cgeq%205)
, the system
![x < 5, x > c](https://tex.z-dn.net/?f=x%20%3C%205%2C%20x%20%3E%20c)
has no solution.