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Citrus2011 [14]
3 years ago
15

HURRYYYY

Mathematics
2 answers:
GarryVolchara [31]3 years ago
6 0

Answer:

There are no real number solutions.

Step-by-step explanation:

2x^{2} +8=0\\2x^{2} =-8\\x^{2} =-4\\x=\sqrt{-4}

Real numbers are a whole range of numbers including: Natural Numbers(1;2;3...), Whole Numbers(0;1;2...), Integers(...;-2;-1;0;1;2;...), Rational Numbers(-0.6; -0.2; 0 ;1.5 etc.) and Irrational Numbers(\sqrt{2};\sqrt{3};π; etc.). All these number comprise Real Numbers.

Imaginary Numbers are the square roots of negative Integers, which is the case for this question.

Radda [10]3 years ago
5 0
There is no help me to do this sorry
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Reduce to simplest form. -\dfrac{1}{3}-\left(-\dfrac{3}{5}\right)=− 3 1 ​ −(− 5 3 ​ )=minus, start fraction, 1, divided by, 3, e
nevsk [136]

Answer:

-1/3 - (-3/5) = 4/15

Step-by-step explanation:

Reduce to simplest form

-1/3 - (-3/5)

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Find the Lowest Common Multiple of 3 and 5

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Use the LCM to Simplify

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Therefore,

-1/3 - (-3/5) = 4/15

7 0
3 years ago
Read 2 more answers
X + 5y = 28 2x + 3y = 21 Solve for x and y.
snow_tiger [21]
First what we gonna do is solve for y.
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x=-5y+28 Then you have to replace x with the equation.
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x=-25+28
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Answer: 3.84 · 10^5

Step-by-step explanation:

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Reptile [31]

We will have the following:

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