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Anit [1.1K]
3 years ago
11

If f(−1) = −3 and f prime of x equals the quotient of 4 times x squared and the quantity x cubed plus 3 , which of the following

is the best approximation for f(–1.1) using local linearization?
–7.2
2.8
–1.2
–3.2

Mathematics
2 answers:
lora16 [44]3 years ago
7 0
<span>f(–1.1) = 4(-1.1)^2 / [(-1.1)^3 + 3]
</span>f(–1.1)  = 4.8 / 1.7
f(-1.1) = 2.8

answer
<span>2.8</span>
KonstantinChe [14]3 years ago
7 0

Answer:

-3.2

Step-by-step explanation:

Linear approximation formula is

f(x)=f(a)+f'(a)(x-a), the value of x is -1.1 and a is -1

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Mark Ronnie and Lisa bought a 75 inch curved 4000 television.Lisa put 650 more than Mark had.Mark had twice as much and then Ron
Alexeev081 [22]

So since you gave all of the equations of everyone's amount that they put in, it saves some work.

Let's add up everyone's contribution and then solve for x:

(2x+500)+x+(650+2x+500)

Then since we know the television costs $2,000, we can set this expression equal to that and simplify terms. Then we can solve for x:

5x+1,650=2000

5x=350

x=70

So since Ronnie put in 'x', we can say that Ronnie paid $70.

Since Mark put in '2x + 500', we can plug in 70 for x to find that Mark paid $640.

And since Lisa put in '650 + 2x + 500', we can plug in 70 for x again to find that Lisa paid $1,290.

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3 years ago
Simplify completely..........​
vitfil [10]

Answer:

\frac{x}{x-1}

Step-by-step explanation:

\frac{3x^2 - 1}{x^2 - 1} - \frac{2x + 1}{x + 1}                                          [ \ x^ 2- 1 = (x-1)(x + 1) \ ]

= \frac{3x^2 - 1}{(x-1)(x  + 1 )} - \frac{2x + 1}{x + 1}\\\\=\frac{(3x^2 - 1)-(2x + 1)(x-1)}{(x + 1)(x-1)}                        [\ Taking \ LCM \  ]

= \frac{(3x^2 - 1)- (2x^2 - 2x + x - 1)}{(x+1)(x-1)}\\\\=\frac{3x^2 - 1 - 2x^2 + x + 1 }{(x+1)(x-1)}\\\\=\frac{x^2 +x}{(x+1)(x-1)}\\\\=\frac{x(x+1)}{(x+1)(x-1)}\\\\=\frac{x}{x-1}

<em><u>Finding LCM :</u></em>

Example :

                 \frac{1}{6} + \frac{1}{3}

6 = 2  x   3

3 = 1   x   3

                \frac{1}{2 \times 3} + \frac{1}{ 3} = \frac{1}{2 \times 3} + \frac{1 \times 2}{ 3 \times 2}  

[ To make the denominators same : the second fraction is multiplied and divided by 2 ]

Similarly :

 (x^2 - 1 ) = (x -1)(x+1)\\\\(x + 1)  = 1 \times (x + 1)

Same rule we applied : multiplied the numerator and denominator of the second term with ( x - 1 )

Therefore the second term becomes ,

                                       \frac{2x + 1}{x + 1} = \frac{(2x + 1)(x - 1)}{(x + 1)( x - 1)}

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The probability of Julia picking 49 is 1/100 ( one number out of 100)

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