To get you answer multiply .3 and 2.7
m∠BCD= m∠ACB ÷ 2 = 134.76° ÷ 2 = 67.38°
Ok done. Thank to me :>
Answer with Step-by-step explanation:
We are given that height of projectile after t seconds is given by

a.h(t)=144 ft






t-3=0
t=3
After 3 s, the height of the project will be 144 feet in the air.
b.h(t)=0




At t=0, the initial position of projectile
At t=6 s , the projectile will hit the ground.
Answer:
<h2>x = 4.545</h2>
Step-by-step explanation:
Given the expression

