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KonstantinChe [14]
3 years ago
8

Joe is playing a game with a regular die.  If the number that turns up is   even, he will gain 5 times the number that comes up.

 If it is odd, he will  lose 10 times the number that comes up.  He tosses a 3. Express the   results as an integer.
Mathematics
1 answer:
kupik [55]3 years ago
4 0
3 is odd
So by the question he will lose 10 times the number that comes up
3*10=-30
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Answer Please! Will give Brainlist! 'Easy'
Nataly [62]

Answer:

i think its 0.4x+7<1 I don't really know

6 0
3 years ago
4 1/2 ​ ÷(−1 3/7​ ) please help and hurry
myrzilka [38]

Hi! I'm happy to help!

To first solve this, we need to make those mixed numbers improper fractions.

To make 4 1/2 an improper fraction, you have to turn 4 into halves (multiply four by 2) then add the extra half, giving you 9/2.

\frac{9}{2}​ ÷(−1\frac{3}{7}​ )

Now, we turn 1 3/7 into an improper fraction. We turn 1 into sevenths (multiply 1 by 7) then add the other 3 sevenths, giving you 10/7.

\frac{9}{2}​ ÷(−\frac{10}{7}​ )

From here, we need to turn this problem into a multiplication problem in order to solve. Since multiplication is the opposite of division, we need to get the opposite of something, so we use our second fraction and flip it.

\frac{9}{2}​ ×(−\frac{7}{10}​ )

Now, we multiply the top by the top, and the bottom by the bottom. (any positive multiplied by a negative gives a negative)

-\frac{63}{20}

<u>Since we cannot simplify, our final answer is -63/20.</u>

I hope this was helpful, keep learning! :D

6 0
2 years ago
Read 2 more answers
Help me please I need this
kupik [55]
24.8 is the correct answer

Explanation: bc it is
8 0
3 years ago
What is 1/2k-3=2-3/4K
laiz [17]

Answer:

1/2k-3=2-3/4k

1/2k+3/4k=2+3

1.25k=5

1.25k/1.25=5/1.25

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4 0
2 years ago
Find a function where f(0)=2 and f(1)=2
xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

f(x) = 2 is a valid solution.

Want something more fun? Why not a parabola? f(x)= ax^2+bx+c.

At this point you have three parameters to play with, and from the fact that f(0)=2 we can already fix one of them, in particular c=2. At this point I would recommend picking an easy value for one of the two, let's say a= 1 (or even a=-1, it will just flip everything upside down) and find out b accordingly:f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1

Our function becomes

f(x) = x^2-x+2

Notice that it works even by switching sign in the first two terms: f(x) = -x^2+x+2

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: f(x) = A cos (kx)

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need A= 2, and at that point the first condition is guaranteed; using the second to find k we get 2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi

f(x) = 2cos(2\pi x)

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

f(x)= 2+sin(2\pi x)

Sky is the limit.

8 0
2 years ago
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