To solve this problem, let us first lay out all the factors of each number.
48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
56 : 1, 2, 4, 7, 8, 14, 28, 56
The greatest number of bouquets that can be made would be equal to the greatest common factor of the two numbers. In this case it would be 8.
Answer:
<span>8 bouquets</span>
y≥-4 or (-4,∞)
Step-by-step explanation:
5. 8/6x + 2
6. -4x - 2
7. y=3
