8,864,321
just put in order greatest to least
You can solve this by using "similar triangles".
In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.
You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:

Substitute for the values of AC, BC, DF and EF:


To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.

Substitute for the values and solve:


We have the value x to be 5.5 units and y to be 6 units.
He walked the same distance to school and back home.
I hope this helped! :-)
Answer:
Charles practiced for the relay race for D. 9 hours last week.
Step-by-step explanation:
First, I would find the ratios the ratios for converting hurdle to javelin and javelin to relay.
Hurdle : Javelin ; 5 : 1.5
Javelin : Relay ; 2.5 : 5 or 1 : 2
Next, find the factors compared to the original numbers for hurdle to javelin.
15 / 5 = 3
To find the amount of javelin time they did, multiply 1.5 by the factor we got, 3.
1.5 * 3 = 4.5
Finally, double 4.5, since Charles does twice as much relay than he does javelin.
4.5 * 2 = 9 hours