A set of negative numbers would contain the number -5.
A set of negative odd numbers would also contain the number -5.
x -3y = 4 multiplie both sides by -2 => -2x +6y = -8
2x +Qy = 8
-2x +6y = -8
2x +Qy = 8
------------------ assume the same terms
0 6y +Qy = 0
6y +Qy = 0
Qy = -6y divide both sides by y and will get
Q = -6
Answer:
110
Step-by-step explanation:
Using the expansion
(a + b)³ = a³ + b³ + 3ab(a + b)
Given
x + 
= 5 ( cube both sides )
(x + )³ = 5³ = 125 ← expand left side using identity
x³ + 
+ 3(x × )(x + ) = 125
x³ + + 3(1)(5) = 125
x³ + + 15 = 125 ( subtract 15 from both sides )
x³ + = 110
Answer:
Since it's a straight line, hence the sum of both angles must be 180°
now,
(2y + 1) + (5y - 3) = 180°
now by solving above equation u can get the value of y!
Step-by-step explanation:
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