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3 years ago

10

Deshaun sells beaded necklaces. Each large necklace sells for $6.20 and each small necklace sells for $4.90. How much will he ea

rn from selling 6 large
necklaces and 1 small necklace?

1 answer:

baherus [9]3 years ago

6 0

Answer:

42.10

Step-by-step explanation:

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Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and

tia_tia [17]

$p=501\cdot503\cdot\cdots\cdot597$

$q=\underbrace{501\cdot503\cdot\cdots\cdot597}_p\cdot599\cdot601$

So we have $q=359,999p$ . Then

$\dfrac1p+\dfrac1q=\dfrac{359,999}{359,999p}+\dfrac1q=\dfrac{359,999+1}q=\dfrac{360,000}q$

and the answer is D.

4 0

3 years ago

Does the following represent a function? <br> f = [ (3, -1), (2, 5), (4, -6), (3, 4), (5, -8) ]

ella [17]

Answer:

Not a function

Since x= produces y- -1 and y=-4, the relation (3,-1),(2,5),(4,-6),(3,4),(5,-8) is not a function.

7 0

3 years ago

Find the value of ....

kaheart [24]

I don't think this is middle school...

(2^8 x 3^-5 x 6^0)^-2 x ((3^-2)/(2^3))^4 x (2^28)

(256 x (1/243))^-2 x ((1/9)/(8))^4 x 268435456

1.05349794239^-2 x (<span>0.01388888888)^4 x 268435456
</span><span>
0.90101623534 x </span><span>3.72108862e-8 x 268435456

</span>8.99999997623

9

9 is your answer.

8 0

4 years ago

B) State a valid formula for multiplying out (A + B)(A − B)

Diano4ka-milaya [45]

(A+B)(A-B) = A^2-B^2.

It's equality constant

8 0

3 years ago

Given: x - 6.3333 ≤ 1.5 .

Inessa05 [86]

Answer:

$x$ or $(-\infty, 47/6]$

Step-by-step explanation:

Note that $6.3333 = 6 1/3 = 19/3 = 38/6$ .

Also, note that $1.5 = 1 1/2 = 3/2 = 9/6$ .

So, the inequality is really equal to $x-38/6$ .

We can then add $38/6$ to both sides to get $x$ .

So, the solution is $x$ , or in interval notation, $(-\infty, 47/6]$

3 0

3 years ago