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Mkey [24]
3 years ago
7

(4/3)^1-x = e^x (solve exponential equation)

Mathematics
1 answer:
Alex777 [14]3 years ago
3 0

we are given

(\frac{4}{3} )^{1-x}=e^x

Since, we have to solve for x

so, firstly we will isolate x on any one side

we can take ln on both sides

ln((\frac{4}{3} )^{1-x})=ln(e^x)

now, we can simplify it

(4-x)ln((\frac{4}{3} )=x

now, we can move all x terms altogether

4*ln(\frac{4}{3})-xln(\frac{4}{3})=x

xln(\frac{4}{3})+x=4*ln(\frac{4}{3})

x(ln(\frac{4}{3})+1)=4ln(\frac{4}{3})

so, we get

x=\frac{4ln(\frac{4}{3})}{(ln(\frac{4}{3})+1)}...........Answer

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