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Neko [114]
3 years ago
12

Find the height. Please help ASAP.

Mathematics
1 answer:
Irina18 [472]3 years ago
5 0
The height would be 36cm.  This is the case because to find the height, first multiply the volume by 2 (You are working backwards from the formula).  Then divide it by the base edge (15).  You will get 36cm.
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Which ordered pair is on the inverse of f(x)?
Karolina [17]
The answer would be A
5 0
3 years ago
Read 2 more answers
.A bucket is filled with 1 3/4 gallons of water. The bucket has a small hole and 1/4 gallon leaks out every hour. How many hours
kenny6666 [7]

Given :

A bucket is filled with 1 3/4 gallons of water.

The bucket has a small hole and 1/4 gallon leaks out every hour.

To Find :

How many hours will it take for the bucket to be completely empty.

Solution :

We know , mixed fraction of form a p/q is given by :

a\ p/q = \dfrac{(a\times q)+p}{q}

So, 1 3/4 = 7/4 .

Let, after t hours bucket is empty.

\dfrac{7}{4}-\dfrac{1}{4}t = 0\\\\t = 7\ hour

Therefore, it takes 7 hours for the bucket to be completely empty.

Hence, this is the required solution.

7 0
3 years ago
A triangle has vertices at a (2,4) b (4,3) c (5,7) which transformation would produce an image with vertices a' (-2,-4) b' (4,-3
zzz [600]

Answer:

180° rotation  

Step-by-step explanation:

The triangle and its image are shown below.

The image is formed by a 180° rotation about the origin, every coordinate is inverted, that is, (x, y) ⟶ (-x, -y).

It is not formed by a 90° rotation or by a reflection across either axis.

6 0
3 years ago
Which quadrilateral and why?
Zigmanuir [339]
Personally you can’t measure you have to be in person but just double it on a piece of paper and you’ll find it out
6 0
3 years ago
We would like to use the power series method to find the general solution to the differential equation d 2y dx2 − 4x dy dx + 12y
Feliz [49]

y=\displaystyle\sum_{n\ge0}a_nx^n

\dfrac{\mathrm dy}{\mathrm dx}=\displaystyle\sum_{n\ge1}na_nx^{n-1}\implies4x\dfrac{\mathrm dy}{\mathrm dx}=4\sum_{n\ge1}na_nx^n=4\sum_{n\ge0}na_nx^n

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}=\sum_{n\ge0}(n+2)(n+1)a_{n+2}x^n

Substituting into the ODE

\dfrac{\mathrm d^2y}{\mathrm dx^2}-4x\dfrac{\mathrm dy}{\mathrm dx}+12y=0

gives

\displaystyle\sum_{n\ge0}\bigg((n+2)(n+1)a_{n+2}-4na_n+12a_n\bigg)x^n=0

so that the coefficients of the series are given according to

\begin{cases}a_0=y(0)\\a_1=y'(0)\\a_{n+2}=\dfrac{4(n-3)a_n}{(n+2)(n+1)}&\text{for }n\ge0\end{cases}

We can shift the index in the recursive part of this definition to get

a_n=\dfrac{4(n-5)a_{n-2}}{n(n-1)}

for n\ge2. There's dependency between coefficients that are 2 indices apart, so we can consider 2 cases:

  • If n=2k, where k\ge0 is an integer, then

k=0\implies n=0\implies a_0=a_0

but since y(0)=0, we have a_0=0 and a_{2k}=0 for all k\ge0.

  • If n=2k+1, then

k=0\implies n=1\implies a_1=a_1

k=1\implies n=3\implies a_3=\dfrac{4(-2)a_1}{3\cdot2}=-\dfrac43a_1

k=2\implies n=5\implies a_5=0

and so a_{2k+1}=0 for all k\ge2. If y'(0)=1, we then have a_1=1 and a_3=-\dfrac43.

So the ODE has solution

y(x)=\displaystyle\sum_{k\ge0}(a_{2k}x^{2k}+a_{2k+1}x^{2k+1})\implies\boxed{y(x)=x-\dfrac43x^3}

8 0
3 years ago
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