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3 years ago

Which test point holds true for y − 2x ≤ 1?

Mathematics

1 answer:

Nataly_w [17]3 years ago

8 0

I think it is (-2,4)

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4 years ago

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Write an equation in slope intercept form for the line that is parallel to y = x - 6 and that passes through the point (-5, -6)

mafiozo [28]

Answer:

y = x - 1

Step-by-step explanation:

First, determine your slope from the given equation y = x - 6

In slope intercept form: y = mx + b, the value for m is the slope.

By looking at "x", there is a coefficient of 1 and therefore 1 is the slope.

Since parallel lines have the same slope, use the slope 1 to rewrite a second eqaution using

the point-slope formula: y - y1 = m(x - x1) and the given point (-5, -6)

y - y1 = m(x - x1)

y - (-6) = 1 (x - (-5)) (Plug in values)

y + 6 = 1(x + 5) (Distribute negatives)

y + 6 = 1x + 5 (Distribute 1 to both terms in the parentheses)

- 6 - 6 (Subtract 6 from both sides)

y = 1x - 1 OR y = x - 1

Check your work by plugging in the given point to your equation:

y = x - 1

-6 = -5 - 1 (Plug in values)

-6 = -6

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3 years ago

Y = 2(6 + 1) + 5(3 + 2)

mamaluj [8]

The answer is 39
Y=14+25

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3 years ago

The parent function f(x) = x2 is translated such that the function g(x) = –x2 + 6x – 5 represents the new function.

zhenek [66]

Answer:

g(x) has an axis of symmetry at x = 3.

g(x) is shifted right 3 units from the graph of f(x)

g(x) is shifted up 4 units from the graph of f(x).

Step-by-step explanation:

The parent function is:

$f(x)=x^2$

The transformed function is $g(x)=-x^2+6x-5$ .

This new function can be rewritten in the vertex form as:

$g(x)=-(x-3)^2+4$

This function is obtained by shifting the parent function 3 units right and 4 units up.

The axis of symmetry is x=3;(x=h) and h=3.

There is no horizontal stretch or compression.

The new function is however reflected in the x-axis

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4 years ago

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Answer:

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3 years ago