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natita [175]
3 years ago
15

How many solutions does the equation 5p - 4p -8 = -2 + 3 have

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
6 0
One solution for this question
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An isosceles triangle has an angle that measures 92° which other angles could be in that isosceles triangle choose all that appl
nignag [31]

Answer:

44

Step-by-step explanation:

The two base angles cannot both be 92 degrees because they would add up to 184 which is more degrees than any triangle has. The apex angle (the top angle) therefore has 92 degrees.

The base angles are equal and found as follows.

2*b + 92 = 180                 Subtract 92 from both sides

2b +92-92 = 180-92

2b = 88                           divide by 2

2b/2=88/2

b = 44

The only angle measurement that fits is 44

6 0
3 years ago
I need help on this question
gtnhenbr [62]
8:20 pm because if Prisha read 60 pages for a half hour, and she read 40 until 8:40, it would be 8:20 pm
8 0
3 years ago
What is 1/10 of 3,000
il63 [147K]
1/10 of 3,000

(1/10)(3000/1)

=(1)(3000)/(10)(1)

=3000/10

=300


7 0
3 years ago
Read 2 more answers
Am I correct? Please check the attachment.
Sergio039 [100]
Yes you are correct
6 0
3 years ago
Solve the equation on the interval [0,2π). cos^4x=cos^4xcscx
Alisiya [41]
\bf cos^4(x)=cos^4(x)csc(x)\\\\
-----------------------------\\\\
cos^4(x)=cos^4(x)\cfrac{1}{sin(x)}\implies cos^4(x)=\cfrac{cos^4(x)}{sin(x)}
\\\\\\
cos^4(x)sin(x)=cos^4(x)\implies cos^4(x)sin(x)-cos^4(x)=0
\\\\\\
cos^4(x)[sin(x)-1]=0\to 
\begin{cases}
cos^4(x)=0\to x=cos^{-1}(0)\\
----------\\
sin(x)-1=0\\
sin(x)=1\to x=sin^{-1}(1)
\end{cases}

\bf \measuredangle x = cos^{-1}(0)\implies \measuredangle x = 
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}
\\\\\\
\measuredangle x=sin^{-1}(1)\implies \measuredangle x=\frac{\pi }{2}

3 0
3 years ago
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