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kicyunya [14]
4 years ago
7

The length of the base of a rectangle prism is 3 feet and its width is 2 feet. The length of the diagonal of the prism is 6 feet

. What is the height of the prism to the nearest tenth a foot?
Mathematics
1 answer:
Ede4ka [16]4 years ago
3 0

Answer:

4.8 feet

Step-by-step explanation:

Since length and width of base is 3 and 2 respectively, we find the diagonal of the base with pythagorean theorem.

3^2+2^2=h^2\\9+4=h^2\\13=h^2\\h=\sqrt{13}

This hypotenuse is the base of a triangle with height as the height of the prism and hypotenuse being the hypotenuse of the prism.

So we can again use pythagorean theorem to solve for the height of the prism (let height of prism be x)

(\sqrt{13} )^2+x^2=6^2\\13+x^2=36\\x^2=36-13\\x^2=23\\x=\sqrt{23}

To the nearest tenth, height is 4.8 feet

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When positive integer x is divided by positive integer y, the remainder is 9. If = 96.12, what is the value of y ? 96 75 48 25 1
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Y= 75.

Lets try to solve it,

When positive integer x is divided by positive integer y, the remainder is 9

=> x=qy+9;

=> x/y=96.12

=>x=96y+0.12y (so q above equals to 96);

=>0.12y=9

=> y=75.

Hence the value of y would be 75.

Learn more about Positive Integer on:

brainly.com/question/1367050

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Answer:

$1200

Step-by-step explanation:

$1200

Step-by-step explanation:

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This means that if you divide 78 by 6.5, you get the equivalent of 1% of the price:

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Now simply multiply this by 100 to get the full answer:

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