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3 years ago

Round 16051 to nearest thousand

Mathematics

1 answer:

svet-max [94.6K]3 years ago

7 0

16,051 —> 16,000 is the answer

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Step-by-step explanation:

Step 1:

We must determine each of the individual values to be able to arrange the given numbers.

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$-5 . \overline{17}$ means that so 1 and 7 in the decimal keep repeating so,

$-5 . \overline{17} = -5.17171717.$

$\sqrt{33} = 33^{\frac{1}{2} } = 5.7445,$ and

$-\frac{26}{5} = -5.2.$

Now that we have all the four values, we can arrange them in ascending order.

Step 2:

There are two negative numbers, the greater a negative number the lesser it is i.e. $-6 < -5.$

So the least value is $-\frac{26}{5}$ which is followed by $-5 . \overline{17}$ .

The other two are positive numbers. As $5.7445 > 6.1666$ so the highest number is $\frac{37}{6}$ .

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3 years ago