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4 years ago

Describe how an ordered pair represents a point on a coordinate plane.

1 answer:

muminat4 years ago

3 0

An ordered pair tells you how many units left and right you move (the x value) and how many units up and down you move (the y value) from the origin (where the x & y lines meet in the middle). An ordered pair is in the form of (x, y). Positive x values move right and negative x values move left. Positive y values move up and negative y values move down.

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ella [17]

Answer:

C
Not clear
A
A
C

Step-by-step explanation:

1) 2x + 246 = 360° (Vertically opposite and angle at a point)

2x = 360 - 246

2x = 114°

x = 114 / 2

x = 57°

3) Since <ABD is a right angle (i.e its sum is 90°)

<CBD = 90° - 75° = 15°

5) <1 = <2 (Vertically opposite angles are equal)

12x + 3 = 10x + 15

12x - 10x = 15 - 3

2x = 12

x = 6

Therefore,

<2 = 10(6) + 15

<2 = 75°

4 0

3 years ago

Find ∂w/∂s and ∂w/∂t using the appropriate Chain Rule.

Vesnalui [34]

Answer:

<h3>The value of $\frac{\partial w}{\partial s}$ is $e^{3t}-18e^{2s+t}$ </h3><h3>The value of $\frac{\partial w}{\partial t}$ is $3e^{3t}-9e^{2s+t}$ </h3><h3>The partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial s}$ is $e^{30}-18$ </h3><h3>The partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial t}=3(e^{30}-3)$ </h3>

Step-by-step explanation:

Given that the Function point are $w=y^3-9x^2y$

$x=e^s$ , $y=e^t$ and s = -5, t = 10

<h3>To find $\frac{\partial w}{\partial s}$ and $\frac{\partial w}{\partial t}$ using the appropriate Chain Rule : </h3>

$w=y^3-9x^2y$

Substitute the values of x and y in the above equation we get

$w=(e^t)^3-9(e^s)^2(e^t)$

$w=e^{3t}-9e^{2s}.e^t$

<h3>Now partially differentiating w with respect to s by using chain rule we have </h3>

$\frac{\partial w}{\partial ∂s}=e^{3t}-9(e^{2s}).2(e^t)$

$=e^{3t}-18e^{2s}.(e^t)$

$=e^{3t}-18e^{2s+t}$

<h3>Therefore the value of $\frac{\partial w}{\partial s}$ is $e^{3t}-18e^{2s+t}$ </h3>

$w=e^{3t}-9e^{2s}.e^t$

<h3>Now partially differentiating w with respect to t by using chain rule we have </h3>

$\frac{\partial w}{\partial t}=e^{3t}.(3)-9e^{2s}(e^t).(1)$

$=3e^{3t}-9e^{2s+t}$

<h3>Therefore the value of $\frac{\partial w}{\partial t}$ is $3e^{3t}-9e^{2s+t}$ </h3>

Now put s-5 and t=10 to evaluate each partial derivative at the given values of s and t :

$\frac{\partial w}{\partial s}=e^{3t}-18e^{2s+t}$

$=e^{3(10}-18e^{2(-5)+10}$

$=e^{30}-18e^{-10+10}$

$=e^{30}-18e^0$

$=e^{30}-18$

<h3>Therefore the partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial s}$ is $e^{30}-18$ </h3>

$\frac{\partial w}{\partial t}=3e^{3t}-9e^{2s+t}$

$=3e^{3(10)}-9e^{2(-5)+10}$

$=3e^{30}-9e{-10+10}$

$=3e^{30}-9e{0}$

$=3e^{30}-9$

$\frac{\partial w}{\partial t}=3(e^{30}-3)$

<h3>Therefore the partial derivative at s=-5 and t=10 is $\frac{\partial w}{\partial t}=3(e^{30}-3)$ </h3>

6 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

juin [17]

Answer: (B) min = -14, max = -3

<u>Step-by-step explanation:</u>

The minimum is the y-value of the vertex of a positive (U-shaped) parabola. In the graph, the vertex is located at (4.5, -14). The y-value of the vertex is -14.

The maximum is the y-value of the vertex of a negative (∩-shaped) parabola. In the graph, the vertex is located at (1.5, -3). The y-value of the vertex is -3.

8 0

3 years ago

Determine whether the situation calls for a survey, an observational study, or an experiment.

grandymaker [24]

Survey

By conducting a survey, you can ask people who have seen the new movie what they think about it. This will be the best approach to get a straightforward answer from these people.

3 0

3 years ago

Adrien has 4 liters of milk. He drinks y liters each day. If Adrien has x liters of milk left after one week, Write a linear equ

notsponge [240]

4•y=x
• means multiply

7 0

3 years ago