Answer:
The answer is "
"
Step-by-step explanation:
Please find the graph file in the attachment.
The area of its tree house's outsides of the square walls and triangular ceilings is equivalent to four squares with four triangles,
![\to A=4[(6)^2+\frac{1}{2} (6)(6)]\\\\](https://tex.z-dn.net/?f=%5Cto%20A%3D4%5B%286%29%5E2%2B%5Cfrac%7B1%7D%7B2%7D%20%286%29%286%29%5D%5C%5C%5C%5C)
![=4[36+\frac{1}{2} (36)]\\\\=4[36+18]\\\\=4[ 54]\\\\=216\ ft^2](https://tex.z-dn.net/?f=%3D4%5B36%2B%5Cfrac%7B1%7D%7B2%7D%20%2836%29%5D%5C%5C%5C%5C%3D4%5B36%2B18%5D%5C%5C%5C%5C%3D4%5B%2054%5D%5C%5C%5C%5C%3D216%5C%20ft%5E2)
If the expression is what I understand it is, this is my answer. (x to the third times x to the negative sixth all squared)
First, i would simplify what is inside the parentheses. x^-6 is the equivalent to
1/x^6. Therefore, the expression inside the parentheses is a fraction: x^3/x^6.
When dividing numbers with exponents, just subtract the exponents.
3-6= -3 so the simplification of the expression in the parentheses is 1/x^3.
To finish the problem, I would apply the square from outside the parentheses to the values inside them. In this way, the exponent would be multiplied by 2.
Our final answer is 1/x^6.
Would it not be one hundred and[insert number]?
Answer:
d + q + p= ¢
Step-by-step explanation:
you add all the variables
Answer:
just do
Step-by-step explanation:
