Question

PLEASE HELP PRECALCULUS SEE ATTACHMENT

Answer 1

Answer:

1+6i

Step-by-step explanation:

Given:

f(x)=x^4 - 2x^3 + 38x^2 - 2 + 37

zero of f(x) = 1-6i

another zero of function = ?

Conjugate Zero theorem:

As per conjugate zero theorem, if a function f(x) has real coefficients and one of zero is a complex number then the conjugate of that complex number will also be a zero of that function i.e. complex zeroes will occur in complex conjugate pairs.

conjugate of 1-6i is 1+6i

hence another zero of f(x) will be 1+6i !