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melisa1 [442]
3 years ago
12

What is 12.1 rounded to the nearest whole number

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0
Since 0.1 is less than 0.5, we could ignore the effect and so 12.1 is rounded to 12
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Multiplying and dividing radical expressions and leaving them in factored form. I am trying to find the best and easy way to get
natka813 [3]

Answer:

\frac{3x + 8}{36 - 2x} / \frac{27x^2 + 72x}{3x^2 - 27} = \frac{(x - 3)(x+3)}{6x(18 - x)}

Step-by-step explanation:

Given

\frac{3x + 8}{36 - 2x} / \frac{27x^2 + 72x}{3x^2 - 27}

Required

Solve

Change / to *

\frac{3x + 8}{36 - 2x} * \frac{3x^2 - 27}{27x^2 + 72x}

Factor out 3

\frac{3x + 8}{36 - 2x} * \frac{3(x^2 - 9)}{3(9x^2 + 24x)}

\frac{3x + 8}{36 - 2x} * \frac{(x^2 - 9)}{(9x^2 + 24x)}

Factorize:

\frac{3x + 8}{36 - 2x} * \frac{(x^2 - 9)}{3x(3x + 8)}

Cancel out 3x + 8

\frac{1}{36 - 2x} * \frac{(x^2 - 9)}{3x}

Factorize:

\frac{1}{2(18 - x)} * \frac{(x^2 - 9)}{3x}

Combine

\frac{x^2 - 9}{2*3x(18 - x)}

\frac{x^2 - 9}{6x(18 - x)}

Express the numerator as a difference of two squares

\frac{(x - 3)(x+3)}{6x(18 - x)}

Hence:

\frac{3x + 8}{36 - 2x} / \frac{27x^2 + 72x}{3x^2 - 27} = \frac{(x - 3)(x+3)}{6x(18 - x)}

8 0
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Answer:

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Step-by-step explanation:

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