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Natasha_Volkova [10]
3 years ago
8

Suppose you want to solve the equation 2a+b=2a, where a and b are nonzero real numbers. describe the solution.

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

b=0       would appreciate brainliest

Step-by-step explanation:

Otherwise, no solution for this equation. You cannot isolate the variable a; its solution value can be anything, but you still find b=0.

2a+b=2a

b+2a=2a

b+2a-2a=2a-2a

b+0=0

b=0

1.   Which becomes 2(1) + 0 = 2(1)

2.    2 + 0 = 2 :

3.    2 = 2. Here we can observe the equality.

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Find m∠UTS, if m∠UTV=x+15, m∠VTS=140∘, and m∠UTS=15x+15.
juin [17]

Answer:

165

Step-by-step explanation:

First, m<UTS=m<UTV+m<VTS by Angle Addition Postulate.  Then, you substitute all the values that you provided for the angles.  15x+15=x+15+140.  You then solve for x.

15x+15=x+155

14x=140

x=10

You then plug back in 10 for X in the value of m<UTS.  15(10)+15=165

8 0
3 years ago
Stephanie rode her new moped to Rod's house. Traveling the side streets, she avaraged 20 mph. To save time on the return trip, t
Illusion [34]

Answer: the distance traveled on the return trip is 70 miles.

Step-by-step explanation:

Let d represent the distance travelled along the side streets.

Let t represent the time spent travelling along the side street

Traveling the side streets, she avaraged 20 mph.

Distance = speed × time

Therefore, distance travelled along the side streets is

d = 40t

On the return trip, Rob's truck took the freeway, averaging 50 mph. The freeway distance is 2 miles less than the distance on the side streets and they saved 24 minutes(24/60 = 0.4 hours). It means that the distance travelled on the return trip is (d - 2) miles and the time spent is

(t - 0.4) hours. Therefore

d - 2 = 50(t - 0.4)

d - 2 = 50t - 20 - - - - - - - - - - -1

Substituting d = 40t into equation 1, it becomes

40t - 2 = 50t - 20

50t - 40t = - 2 + 20

10t = 18

t = 18/10 = 1.8

d = 40t = 40 × 1.8

d = 72

The distance on the return trip is

72 - 2 = 70 miles.

3 0
3 years ago
A wire is in the shape of a rectangle of length 14cm. Find its breadth if the same wire is re- bent into a square of side 13cm.
lara [203]
Length= 40cm

Breadth= 22cm

Perimeter of the rectangle= Length of the wire

=2(l+b)= 2(40cm + 22cm)

=2\times62cm = 124cm

Now, the wire is rebent into a square.

Perimeter= 124cm

4\times side=124

Therefore side= \frac{124}{4}cm= 31cm

So, the measure of each side= 31cm

Area of rectangular shape= l\times b

=40cm\times22cm

=880cm^2

Area of a square shape= \left(Side\right)^2

=\left(31\right)^2=961cm^2

Since 961cm^2\ >\ 880cm^2

Hence, the square encloses more area.
7 0
2 years ago
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steposvetlana [31]

Answer:

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Step-by-step explanation:

Her mistake was adding a negative sign in the one

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6 0
3 years ago
The price paid for a $15 shirt after a 45% discount is applied​
Tamiku [17]

Answer:

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