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const2013 [10]
3 years ago
5

Prove the identity (sin3A+sinA)/2sin2A= cosA​

Mathematics
1 answer:
jarptica [38.1K]3 years ago
7 0

Step-by-step explanation:

\frac{ \sin(3A)  +  \sin(A) }{2 \sin(2A) }

Using the trigonometric identity

\sin(x)  +  \sin(y)  = 2 \sin( \frac{x + y}{2} )  \cos( \frac{x - y}{2} )

Rewrite the expression

We have

\frac{2 \sin(2A)  \cos(A) }{2 \sin(2A) }

Reduce the fraction with 2

That's

\frac{ \sin(2A)  \cos(A) }{ \sin(2A) }

Reduce the fraction with sin 2A

We have the final answer as

<h2>cos A</h2>

As proven

Hope this helps you

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<span>Answer: 199.81
Given:
1 hundred
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9 ones
8 tenths
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thus;
1 hundred = 1 x 100 = 100
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add: 100 + 90 + 9 + .8 + .001 = 199.81
That is: one hundred ninety-nine and eighty-one hundredths</span>


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