For the process of transformation of glucose into pyruvate, NAD⁺ is converted into NADH. These same NADH molecules are then reutilised on the pyruvate to lactic acid reaction and are therefore transformed back into NAD⁺ molecules that will again be used for another glycolysis reaction.
From the first rectangle, on the left, to the last rectangle, on the right, it comes NAD⁺ - NADH - NADH - NAD⁺.
The answer is A, and this is true because trauma can not be transmitted or caught by humans or animals but a virus , faulty nutrition & congenital defects can. hope this helps :)
<span>Animals gradually adapt to changes within their environment over time. This gives them a better chance of surviving rather than going extinct because of the change. Say there is a gene mutation affecting color within a population of beetles in a rain-forest. All of the beetles used to be red, but now a few of them have experienced a gene mutation and are green. Because they live in a rain-forest, it is likely that the green beetles would blend in with their surroundings far better than the original red beetles, and those red beetles would be wiped out by predators because they are easier to spot. The green beetles would live on and flourish, and their population would increase. Soon there would be few or none red beetles, and many green beetles.</span>
Answer:
No, it is not possible
Explanation:
Humans use the ABO blood group system where the A and B alleles are dominant over allele O but codominant with one another.
This system is such that;
Type A can only have genotype: iAiA or iAi
Type B can only have genotype: iBiB or iBi
Type AB can only have genotype: iAiB
Type O can only have genotype: ii
According to this question, a woman has blood Type A (iAiA or iAi) and her baby has blood Type AB (iAiB). This means that the father definitely contributed the allele B in order to have a baby with type AB. It also means that, according to the question, IT IS NOT POSSIBLE FOR A "Type A" father to produce that baby (see the punnet square attached).
Note: The father must contain an allele B in his genotype i.e. the father must be either type B (iBiB or iBi) or type AB (iAiB)
