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Schach [20]
3 years ago
14

Parking in a student lot costs $2 for the first half hour and $1.75 for each hour thereafter. A partial hour is charged the same

as a full hour. What is the longest time that a student can park in this lost for $7?
Mathematics
2 answers:
bixtya [17]3 years ago
7 0
The longest time that a student can park in this parking lot for $7 is 2 in a half hours
Masteriza [31]3 years ago
3 0

An easier way to think of this problem is just keep adding for each additional hour: 


0.5 hours --> $2 

1.5 hrs --> $3.75 

2.5 hrs --> $5.50 

3.5 hrs --> $7.25 


and since you can only spend $7, the maximum time is 2.5 hours

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Olenka [21]
Hey John

Let's start solving #1

x/4 = 3.5/28
Cross multiply
(x)(28) = (3.5)(4)
28x = 14
Divide both sides by 28
28x/28 = 14/28
x = 1/2

Next, let's solve the second one

\frac{3}{5} +  \frac{4}{5x} +  \frac{7}{10x} + 1 \frac{1}{2} = 5 \frac{3}{5}
Simplifies to:
\frac{105x+75}{50x} =  \frac{28}{5}
Cross multiply
(105x + 75)(5) = (28)(50x)
525x + 375 = 1400x
Subtract 1400x to both sides
525x + 375 - 1400x = 1400x - 1400x
-875x + 375 = 0
Then subtract 375 from both sides
-875x + 375 - 375 = 0 - 375
-875x = -375
To find x, divide both sides by -875
-875x/-875 = -375/-875
x = 3/7

Let me know if you have questions about the answer.

Best of luck with your studies!

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disa [49]

Answer:

x=45

Step-by-step explanation:

this should be right

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