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Schach [20]
2 years ago
14

Parking in a student lot costs $2 for the first half hour and $1.75 for each hour thereafter. A partial hour is charged the same

as a full hour. What is the longest time that a student can park in this lost for $7?
Mathematics
2 answers:
bixtya [17]2 years ago
7 0
The longest time that a student can park in this parking lot for $7 is 2 in a half hours
Masteriza [31]2 years ago
3 0

An easier way to think of this problem is just keep adding for each additional hour: 


0.5 hours --> $2 

1.5 hrs --> $3.75 

2.5 hrs --> $5.50 

3.5 hrs --> $7.25 


and since you can only spend $7, the maximum time is 2.5 hours

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A machine can make 56 parts in 4 hours.It can also make 70 parts in 5 hours. Write an equation that relates the number of parts
ira [324]

Answer:

126 parts in 9 and a half hours

Step-by-step explanation:

56 parts in 4 hours

that means 56 parts in 240 mins

9 hours and 30 minutes in minutes is 570 minutes

56m parts:240 mins

                 540 mins

to get to 540 from 240, you multiply by 2.25.

you can work this out by doing 540 divided by 240

now, multiply 56 by 2.25.

the answer is 126 parts

5 0
3 years ago
What is 1/3. of 4/5 I need help
levacccp [35]
To do this multiply 1 by 4, then 3 by 5.  4 over 15 is your answer.
6 0
3 years ago
Read 2 more answers
A house was valued at $100,000 in the year 1987. The value appreciated to $165,000 by the year 2002.
iris [78.8K]

Answer:

  A) The annual multiplier was 1.0339; the annual increase was 0.0339 of the value.

  B) 3.39% per year

  C) $182,000

Step-by-step explanation:

A) Let's let t represent years since 1987. Then we can fill in the numbers and solve for r.

  165000 = 100000(1 +r)^15

  1.65^(1/15) = 1 +r . . . . . divide by 100,000; take the 15th root

  1.03394855265 -1 = r ≈ 0.0339

The value was multiplied by about 1.0339 each year.

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B) The value increased by about 3.39% per year.

__

C) S = $100,000(1.03394855265)^18 ≈ $182,000

8 0
3 years ago
I just need to find this data set out, please anyone?​
rewona [7]

Answer:

Ok so...

Mean: 68.76

Median: 72

Range: 85

Step-by-step explanation:

3 0
3 years ago
How to find equation hyperbola with asymptotes, center and transverse?
lapo4ka [179]
The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
h represents the x value of the coordinate
k value represents the y value of the coordinate 
together they represent a point, which is the center
So (h,k) is (x,y)

The asymptote is y-k = +/- b/a (x-h)
The transverse is the line that goes through the hyperbola. 
6 0
3 years ago
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