R + A + G = 95.....lol...rag
G = 3A
A = R - 10
G = 3(R - 10)...G = 3R - 30
R + A + G = 95
R + (R - 10) + (3R - 30) = 95
5R - 40 = 95
5R = 95 + 40
5R = 135
R = 135/5
R = 27 <===Raini sent 27
A = R - 10
A = 27 - 10
A = 17 <===Austin sent 17
G = 3R - 30
G = 3(27) - 30
G = 81 - 30
G = 51 <==Goran sent 51
Answer:
0.15 is the answer
Step-by-step explanation:
Answer:
g(x) = -9(x + 1)2 - 7
Step-by-step explanation:
Answer:
379,442 AU
Step-by-step explanation:
The angle bisector is the altitude of the triangle. The resulting right triangle has a distance of 1 AU opposite the 0.000151° angle. The length we're interested in is the hypotenuse of the triangle. The relevant trig relation is ...
Sin = Opposite/Hypotenuse
Hypotenuse = Opposite/Sin
E-S distance = (1 AU)/sin(0.000151°) ≈ 379,442 AU
The star is about 379,442 AU from Earth.