Y= x²- 6x +7
Vertex form is y= a(x-h)² +k
The vertex form of this equation would be y= (x-3)²- 2 because if we transform to the standard form it would be equal to y= x²-6x+7 so we just have to complete the perfect square (which means to complete, following the rules, with the numbers that will make this equation right in the standard form).
How our x² is equal to 1 on our standard form (like it is not 2x², it is just x²), our ''a'' on the vertex form is 1 so we simply don't have to write the 1 in front of it so it stays y= 1(x-3)² -2 or y=(x-3)²-2. Look how it works: (x-3)² we use the rule of a²+2ab+c² which is the square of the first x² plus two times the first term times the second -6x plus the square of the last term (-3)² = 9 so we have x²-6x+9 - 2 that gives us the standard form x²-6x+7. So, that's true that the vertex form is y=(x-3)²-2
Answer:
As the points are collinear, the slope of the line joining
any two points, should be same as the slope of the line joining two other
points.
Slope of the line passing through points (x
1
,y
1
) and (x
2
,y
2
) =
x
2
−x
1
y
2
−y
1
So, slope of the line joining (p,0),(0,q)= Slope of the line joining
(0,q) and (1,1)
0−p
q−0
=
1−0
1−q
−
p
q
=1−q
Dividing both sides by q,
−
p
1
=
q
1
−1
=>
p
1
+
q
1
=1
Answer:
from least to greatest
1.25, -(-2). 3, 4
Step-by-step explanation:
it's just from least to greatest and to negatives cancel out leading 2 to become a positive number. The difference between 1.25 and 2 is 0.75 so you would have them 0.75 distance a part and the rest with 1 distance apart.
Answer:
coding
release
design
planning
Step-by-step explanation:
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