3 years ago

Simplify the imaginary number (square root symbol) -8

1 answer:

7 0

Sqrt(-8) = sqrt(-1)*sqrt(8)
= i *sqrt(4)*sqrt(2)
= i * 2*sqrt(2) (answer)

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aivan3 [116]

<h3>Therefore either $x = \frac{-3+\sqrt{17}}{2}$ or, $x = \frac{-3-\sqrt{17}}{2}$ </h3>

Step-by-step explanation:

$3x^2 +9x -6=0$ $x = \frac{-b\pm\sqrt{b^2- 4ac} }{2a}$

$\Leftrightarrow x = \frac{-9\pm\sqrt{9^2- 4.3(-6)} }{2.3}$ here a = 3 ,b = 9 and c= -6

$\Leftrightarrow x = \frac{-9\pm\sqrt{153} }{6}$

$\Leftrightarrow x = \frac{3(-3\pm\sqrt{17}) }{6}$

$\Leftrightarrow x = \frac{-3\pm\sqrt{17}}{2}$

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Step-by-step explanation:

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lys-0071 [83]

Answer:

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